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6.9 USING Equations that Factor
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Problem Solving Guidelines
Phase 1: UNDERSTAND the problem What am I trying to find? What Data am I Given? Have I ever solved a Similar problem? Phase 2: Develop and carry out a PLAN What strategies might I use to solve the problem? How can I correctly carry out the strategies I selected? Phase 3: Find the ANSWER and CHECK Does the proposed solution check? What is the answer to the problem? Does the answer seem reasonable? Have I stated the answer clearly?
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Example #1 The product of one more than a number and one less than a number is 8. One more than a number: x + 1 One less than a number: x β 1 Product of both IS 8 (x + 1)(x β 1) = 8 π₯ 2 β1=8 π₯ 2 β1 β8=0 π₯ 2 β9=0 (x β 3)(x + 3) = 0 X = 3 or x = -3 Note: They both check out, so they are both solutions.
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Example #2 The square of a number minus twice the number is 48. Find the number. Let x = the Number. The square of a number: π π Twice the Number: 2x π π βππ=ππ π π - 2x β 48 = 0 (x β 8)(x + 6) = 0 x = 8 or x = -6 Note: They both Check Out, so they are both solutions.
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Example # 3 The area of the foresail on a 12-meter racing yacht is square meters. The sailβs height is 8.75 meters greater than its base. Find its base and height. Area = 1 2 Γ base Γ height Let h = the sailβs height And h β 8.75 = the length of the sailβs base 1 2 Γ π» β8.75 Γπ»=93.75 (H β 8.75)H = π» 2 β8.75π»=187.5 π» 2 β8.75π» β187.5=0 (H β 18.75)(H + 10) = 0 H β = 0 OR H + 10 = 0 H = H = -10
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EXAMPLE #4 The Product of two consecutive Integers is 156. Find the Integers. First Integer = x Second Integer = x + 1 X(x+1) = 156 π₯ 2 +π₯=156 π₯ 2 +π₯ β156=0 (x β 12)(x + 13) = 0 X β 12 = 0 OR x + 13 = 0 X = 12 OR x = -13 Integers are 12 and 13 OR Integers are -12 and -13
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classwork 1.The Product of Seven Less Than a Number and eight less than a number is The Product of one more than a number and one less than the number is One more than twice the square of a Number is The Width of a rectangular card is 2cm less than the length. The area is 15 ππ 2 . Find the length and width. 5. The product of two consecutive Integers is 462. Find the Integers.
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1.The Product of Seven Less Than a Number and eight less than a number is 0.
Seven less than a Number: x β 7 Eight less than a number: x β 8 Product: Multiply the 2 Together (x β 7)(x β 8) = 0 x β 7 = 0 or x β 8 = 0 x = 7 x = 8
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2. The Product of one more than a number and one less than the number is 24.
One more than a number: x + 1 One less than a number: x β 1 (x + 1)(x β 1) = 24 π₯ 2 β1=24 π₯ = 0 (x + 5)(x β 5) = 0 X + 5 = 0 or x β 5 = 0 X = -5 or x = 5
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3. One more than twice the square of a Number is 73.
The square of a number: π₯ 2 Twice that: 2 π₯ 2 One more than THAT: 2 π₯ π₯ 2 +1=73 2 π₯ 2 β72=0 2( π₯ ) = 0 2(x + 6)(x β 6) = 0 2 β 0 x + 6= 0 or x β 6 = 0 x = -6 x = 6
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4. The Width of a rectangular card is 2cm less than the length
4. The Width of a rectangular card is 2cm less than the length. The area is 15 ππ 2 . Find the length and width. A = lw A = 15 ππ 2 Width(w) = l β 2 L(l β 2) = 15 πΏ 2 β2πΏ=15 πΏ 2 β2πΏ β15=0 (L + 3)(L β 5) = 0 L = -3 or l = 5 Which one makes more sense? Can you have a Negative length? L = 5cm, Therefore W= 5 β 2 = 3cm
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5. The product of two consecutive Integers is 462. Find the Integers.
First integer: x Second Integer: x + 1 x(x+1) = 462 π₯ 2 + x = 462 π₯ 2 +π₯ β462=0 (x β 21)(x + 22) = 0 X = 21 or x = -22 So Either 21 and 22 OR -21 and -22
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