1. Splash Screen

3. Key Concept: Horizontal Line Test
Five-Minute Check
Then/Now
New Vocabulary
Key Concept: Horizontal Line Test
Example 1: Apply the Horizontal Line Test
Key Concept: Finding an Inverse Function
Example 2: Find Inverse Functions Algebraically
Key Concept: Compositions of Inverse Functions
Example 3: Verify Inverse Functions
Example 4: Find Inverse Functions Graphically
Example 5: Real-World Example: Use an Inverse Function
Lesson Menu

4. Given f (x) = 3x and g (x) = x 2 – 1, find (f ● g)(x) and its domain.B. C. D.
5–Minute Check 1

5. Given f (x) = 3x and g (x) = x 2 – 1, find (f ● g)(x) and its domain.B. C. D.
5–Minute Check 1

6. Given f (x) = 3x and g (x) = x 2 – 1, find and its domain.B. C. D.
5–Minute Check 2

7. Given f (x) = 3x and g (x) = x 2 – 1, find and its domain.B. C. D.
5–Minute Check 2

8. Given f (x) = 3x and g (x) = x 2 – 1, find [g ○ f](x) and its domain.B. C. D.
5–Minute Check 3

9. Given f (x) = 3x and g (x) = x 2 – 1, find [g ○ f](x) and its domain.B. C. D.
5–Minute Check 3

10. Find two functions f and g such that h (x) = [f ○ g](x).B. C. D.
5–Minute Check 4

11. Find two functions f and g such that h (x) = [f ○ g](x).B. C. D.
5–Minute Check 4

12. You found the composition of two functions. (Lesson 1-6)
Use the graphs of functions to determine if they have inverse functions.
Find inverse functions algebraically and graphically.
Then/Now

13. inverse relation
inverse function
one-to-one
Vocabulary

14. INVERSE RELATIONS & FUNCTIONS
Horizontal Line Test
DAY 1
HW: Pg , #’s 1-24, 46-49, 50-53

15. Key Concept 1

16. Apply the Horizontal Line Test
A. Graph the function f (x) = 4x 2 + 4x + 1 using a graphing calculator, and apply the horizontal line test to determine whether its inverse function exists. Write yes or no.
The graph of f (x) = 4x 2 + 4x + 1 shows that it is possible to find a horizontal line that intersects the graph of f (x) more than once. Therefore, you can conclude that f –1 does not exist.
Answer:
Example 1

17. Apply the Horizontal Line Test
A. Graph the function f (x) = 4x 2 + 4x + 1 using a graphing calculator, and apply the horizontal line test to determine whether its inverse function exists. Write yes or no.
The graph of f (x) = 4x 2 + 4x + 1 shows that it is possible to find a horizontal line that intersects the graph of f (x) more than once. Therefore, you can conclude that f –1 does not exist.
Answer: no
Example 1

18. Apply the Horizontal Line Test
B. Graph the function f (x) = x 5 + x 3 – 1 using a graphing calculator, and apply the horizontal line test to determine whether its inverse function exists. Write yes or no.
The graph of f (x) = x 5 + x 3 – 1 shows that it is not possible to find a horizontal line that intersects the graph of f (x) more than one point. Therefore, you can conclude that f –1 exists.
Answer:
Example 1

19. Apply the Horizontal Line Test
B. Graph the function f (x) = x 5 + x 3 – 1 using a graphing calculator, and apply the horizontal line test to determine whether its inverse function exists. Write yes or no.
The graph of f (x) = x 5 + x 3 – 1 shows that it is not possible to find a horizontal line that intersects the graph of f (x) more than one point. Therefore, you can conclude that f –1 exists.
Answer: yes
Example 1

20. Graph the function using a graphing calculator, and apply the horizontal line test to determine whether its inverse function exists. Write yes or no.
A. yes
B. yes
C. no
D. no
Example 1

21. Graph the function using a graphing calculator, and apply the horizontal line test to determine whether its inverse function exists. Write yes or no.
A. yes
B. yes
C. no
D. no
Example 1

22. Find the Inverse of a Function Algebraically
Key Concept 2

23. A. Determine whether f has an inverse function for
Find Inverse Functions Algebraically
A. Determine whether f has an inverse function for
. If it does, find the inverse function and state any restrictions on its domain.
The graph of f passes the horizontal line test. Therefore, f is a one-one function and has an inverse function. From the graph, you can see that f has domain
and range Now find f –1. 
Example 2

24. Find Inverse Functions Algebraically
Example 2

25. 2xy – y = x Isolate the y-terms. y(2x –1) = x Factor.
Find Inverse Functions Algebraically
Original function
Replace f(x) with y.
Interchange x and y.
2xy – x = y Multiply each side by 2y – 1. Then apply the Distributive Property.
2xy – y = x Isolate the y-terms.
y(2x –1) = x Factor.
Example 2

26. Find Inverse Functions Algebraically
Divide.
Example 2

27. Find Inverse Functions Algebraically
From the graph, you can see that f –1 has domain and range The domain and range of f is equal to the range and domain of f –1, respectively. Therefore, it is not necessary to restrict the domain of f –1. 
Answer:
Example 2

28. Find Inverse Functions Algebraically
From the graph, you can see that f –1 has domain and range The domain and range of f is equal to the range and domain of f –1, respectively. Therefore, it is not necessary to restrict the domain of f –1. 
Answer: f –1 exists;
Example 2

29. Find Inverse Functions Algebraically
B. Determine whether f has an inverse function for If it does, find the inverse function and state any restrictions on its domain.
The graph of f passes the horizontal line test. Therefore, f is a one-one function and has an inverse function. From the graph, you can see that f has domain and range Now find f –1.
Example 2

30. Original function Replace f(x) with y. Interchange x and y.
Find Inverse Functions Algebraically
Original function
Replace f(x) with y.
Interchange x and y.
Divide each side by 2.
Square each side.
Example 2

31. From the graph, you can see that f –1 has domain
Find Inverse Functions Algebraically
Add 1 to each side.
Replace y with f –1(x).
From the graph, you can see that f –1 has domain
and range By restricting the domain of f –1 to , the range remains Only then are the domain and range of f equal to the range and domain of f –1, respectively. So,
Example 2

32. Find Inverse Functions Algebraically
Answer:
Example 2

33. Answer: f –1 exists with domain ;
Find Inverse Functions Algebraically
Answer: f –1 exists with domain ;
Example 2

34. Determine whether f has an inverse function for
Determine whether f has an inverse function for If it does, find the inverse function and state any restrictions on its domain. A. B. C.
D. f –1(x) does not exist.
Example 2

35. Determine whether f has an inverse function for
Determine whether f has an inverse function for If it does, find the inverse function and state any restrictions on its domain. A. B. C.
D. f –1(x) does not exist.
Example 2

36. DAY 2 INVERSE RELATIONS & FUNCTIONS HW: Pg. 52 #’s 27-36
Use Composition of Function to Prove Inverses
DAY 2
HW: Pg. 52 #’s 27-36

37. Key Concept 3

38. Show that f [g (x)] = x and g [f (x)] = x.
Verify Inverse Functions
Show that f [g (x)] = x and g [f (x)] = x.
Example 3

39. Verify Inverse Functions
Because f [g (x)] = x and g [f (x)] = x, f (x) and g (x) are inverse functions. This is supported graphically because f (x) and g (x) appear to be reflections of each other in the line y = x.
Example 3

40. Verify Inverse Functions
Answer:
Example 3

41. Verify Inverse Functions
Answer:
Example 3

42. Show that f (x) = x 2 – 2, x  0 and are inverses of each other.B. C. D.
Example 3

43. Show that f (x) = x 2 – 2, x  0 and are inverses of each other.B. C. D.
Example 3

44. Use the graph of relation A to sketch the graph of its inverse.
Find Inverse Functions Graphically
Use the graph of relation A to sketch the graph of its inverse.
Example 4

45. Find Inverse Functions Graphically
Graph the line y = x. Locate a few points on the graph of f (x). Reflect these points in y = x. Then connect them with a smooth curve that mirrors the curvature of f (x) in line y = x.
Answer:
Example 4

46. Find Inverse Functions Graphically
Graph the line y = x. Locate a few points on the graph of f (x). Reflect these points in y = x. Then connect them with a smooth curve that mirrors the curvature of f (x) in line y = x.
Answer:
Example 4

47. Use the graph of the function to graph its inverse function.B. C. D.
Example 4

48. Use the graph of the function to graph its inverse function.B. C. D.
Example 4

49. Use an Inverse Function
A. MANUFACTURING The fixed costs for manufacturing one type of stereo system are $96,000 with variable cost of $80 per unit. The total cost f (x) of making x stereos is given by f(x) = 96, x. Explain why the inverse function f –1(x) exists. Then find f –1(x).
The graph of f (x) = 96, x passes the horizontal line test. Therefore, f (x) is a one-to one function and has an inverse function.
Example 5

50. f (x) = 96,000 + 80x Original function
Use an Inverse Function
f (x) = 96, x Original function
y = 96, x Replace f (x) with y.
x = 96, y Interchange x and y.
x – 96,000 = 80y Subtract 96,000 from each side.
Divide each side by 80.
Replace y with f –1(x).
Example 5

51. Use an Inverse Function
Answer:
Example 5

52. Answer: The graph of f (x) passes the horizontal line test.
Use an Inverse Function
Answer: The graph of f (x) passes the horizontal line test.
Example 5

53. Use an Inverse Function
B. MANUFACTURING The fixed costs for manufacturing one type of stereo system are $96,000 with variable cost of $80 per unit. The total cost f (x) of making x stereos is given by f (x) = 96, x. What do f –1(x) and x represent in the inverse function?
In the inverse function, x represents the total cost and f –1 (x) represents the number of stereos.
Answer:
Example 5

54. Use an Inverse Function
B. MANUFACTURING The fixed costs for manufacturing one type of stereo system are $96,000 with variable cost of $80 per unit. The total cost f (x) of making x stereos is given by f (x) = 96, x. What do f –1(x) and x represent in the inverse function?
In the inverse function, x represents the total cost and f –1 (x) represents the number of stereos.
Answer: In the inverse function, x represents the total cost and f –1(x) represents the number of stereos.
Example 5

55. Use an Inverse Function
C. MANUFACTURING The fixed costs for manufacturing one type of stereo system are $96,000 with variable cost of $80 per unit. The total cost f (x) of making x stereos is given by f (x) = 96, x. What restrictions, if any, should be placed on the domain of f (x) and f –1(x)? Explain.
The function f (x) assumes that the fixed costs are nonnegative and that the number of stereos is an integer. Therefore, the domain of f(x) has to be nonnegative integers. Because the range of f (x) must equal the domain of f –1(x), the domain of f –1(x) must be multiples of 80 greater than 96,000.
Example 5

56. Use an Inverse Function
Answer:
Example 5

57. Use an Inverse Function
Answer: The domain of f (x) has to be nonnegative integers. The domain of f –1(x) is multiples of 80 greater than 96,000.
Example 5

58. Use an Inverse Function
D. MANUFACTURING The fixed costs for manufacturing one type of stereo system are $96,000 with variable cost of $80 per unit. The total cost f (x) of making x stereos is given by f (x) = 96, x. Find the number of stereos made if the total cost was $216,000.
Because , the number of stereos made for a total cost of $216,000 is 1500.
Answer:
Example 5

59. Use an Inverse Function
D. MANUFACTURING The fixed costs for manufacturing one type of stereo system are $96,000 with variable cost of $80 per unit. The total cost f (x) of making x stereos is given by f (x) = 96, x. Find the number of stereos made if the total cost was $216,000.
Because , the number of stereos made for a total cost of $216,000 is 1500.
Answer: 1500 stereos
Example 5

60. EARNINGS Ernesto earns $12 an hour and a commission of 5% of his total sales as a salesperson. His total earnings f (x) for a week in which he worked 40 hours and had a total sales of $x is given by f (x) = x. Explain why the inverse function f –1(x) exists. Then find f –1(x).
Example 5

61. A. B. C. D.
Example 5

62. A. B. C. D.
Example 5

63. End of the Lesson