1. Ion Concentration

2. 1. What is the concentration of each ion in a 0.300 M AlCl3 solution?
0.3 mole
AlCl3
Al3+ +
3Cl-
Al3+
Cl-
0.3 mole
0.3 mole
0.300 M
0.300 M
0.900 M
Cl-
0.3 mole

3. 2. What is the concentration of each ion in the solution formed by dissolving 80.0 g of CaCl2 in mL of water?
1 mol
80.0 g x
111.1 g
[ CaCl2 ] = =
1.20 M L
CaCl2
Ca2+ +
2Cl-
1.20 M
1.20 M
2.40 M

4. The molarity decreases when water is added by a factor of: V1/V2
3. If 1.25 L of M Aluminum sulphate solution is added to 4.75 L of water, what is the resulting concentration of each ion?
M1V1 = M2V2
(0.560 M)(1.25 L) = M2(6.00 L)
M2 = M
Al2(SO4)3
2Al3+ +
3SO42- M
0.233 M
0.350 M
x 3/2
Shortcut
The molarity decreases when water is added by a factor of: V1/V2
Al2(SO4) → Al SO42-
1.25
6.00
0.560 M
x 2
0.233 M
x 3/2
0.350 M

5. 4. If the [SO42-] = M in 20.0 mL of Ga2(SO4)3, determine the [Ga3+] and the molarity of the solution.
Ga2(SO4)3
2 Ga3+ +
3SO42- M M
0.100 M

6. 5. If the [Cl-] = M, calculate the number of grams of AlCl3 that would be dissolved in 3.00 L of water.
AlCl3
Al3+ +
3Cl- M
0.400 M
3.00 L
mol
133.5 g x x =
53.4 g
1 L
1 mol

7. 6. If 40. 0 mL of 0. 400 M potassium chloride solution is added to 60
6. If 40.0 mL of M potassium chloride solution is added to 60.0 mL of
0.600 M calcium chloride, what is the resulting concentration of each ion. v1
KCl K+ +
Cl_
40.0
100.0
0.400 M
0.160 M
0.160 M v2 v1
CaCl2
Ca2+
Cl_
60.0
100.0
0.600 M
0.360 M
0.720 M v2
[Cl_] = M M = M