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Terry A. Ring Chemical Engineering University of Utah

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1 Terry A. Ring Chemical Engineering University of Utah
Distillation Terry A. Ring Chemical Engineering University of Utah

2 Marginal Vapor Rate Marginal Annualized Cost~ Marginal Vapor Rate
Marginal Annualized Cost proportional to Reboiler Duty (Operating Cost) Reboiler Area (Capital Cost) Condenser Duty (Operating Cost) Condenser Area (Capital Cost) Diameter of Column (Capital Cost) Vapor Rate is proportional to all of the above

3 Revisit Marginal Vapor Flow Rate – HW3
Case B Marginal Vapor Flow Rate (MVFR) Sum of Vapor Flows for all columns in the Sequence V=ΣD Case A = Direct Sequence A/BC, B/C Is Case B- MVFR Direct Squence Indirect Sequence AB/C, A/B Distillate Products Species Boiling Pt (C) Feed Flow Direct Secuence Indirect Sequence (kmole/hr) C1 C2 Benzene 80.1 100 Toluene 110.6 Ethylbenzene 136 p-xylene 138 m-xylene 139 Total D 200 300 Case A

4 HW 3 Case A – Direct Sequence
Using ΣDi only, Case B – Best via Marginal Vapor Flow Rate Direct Sequence These are both the same! Your boss is an idiot!!

5 Revisit Marginal Vapor Flow Rate – HW3
Case B Marginal Vapor Flow Rate Sum of Vapor Flows for all columns in the Sequence V=Σ[D*(1.2*Rmin+1)] Distillate Products Species Boiling Pt (C) Feed Flow Direct Secuence Indirect Sequence (kmole/hr) C1 C2 Benzene 80.1 100 Toluene 110.6 Ethylbenzene 136 p-xylene 138 m-xylene 139 Total D 200 300 Case A

6 Aspen Simulation with DSTWU Columns

7 DSTWU Direct Sequence Results

8 Direct Sequence – Case A Results
Case A Case B Species Boiling Pt (C) Feed Flow Direct Secuence = A/BC, B/C Indirect Sequence = AB/C, A/B (kmole/hr) R.min D for CI D for C2 D for C1 C2 Benzene 80.1 100 1.26 1.32 Toluene 110.6 3.98 1.37 Ethylbenzene 136 p-xylene 138 m-xylene 139 Total V= Σ[D*(1.2*Rmin+1)] = 828.8 787.2 Note: Rmin is in the row of the light key component Kmole/Hr

9 DSTWU Indirect Sequence Results

10 Marginal Vapor Flow Rates
Case A Case B (MVFR Case) Species Boiling Pt (C) Feed Flow Direct Secuence = A/BC, B/C Indirect Sequence = AB/C, A/B (kmole/hr) R.min D for CI D for C2 D for C1 C2 Benzene 80.1 100 1.26 1.32 Toluene 110.6 3.98 1.37 Ethylbenzene 136 p-xylene 138 m-xylene 139 Total V= Σ[D*(1.2*Rmin+1)] = 828.8 787.2 Note: Rmin is in the row of the light key component

11 Azeotropic Distillation
Multi-component Distillation with Azeotropes Breaking a Binary Distilation Azeotrope

12 Heterogeneous Azeotropic Distillation
Example: Dehydration of Ethanol Liquid-Liquid Equilibrium Line Try toluene as an entrainer What are the zones of exclusion?

13 Ethanol/Water Distillation with Toluene to Break Azeotrope
M1 M2 D1 Distillation Line Tie Line

14 Ethanol/Water Distillation with Benzene To Break Azeotrope (black line)
Liquid-Liquid Equilib Line

15 How To Break Azeotropes with Entrainer
Separation Train Synthesis Identify Azeotropes Some distillations are not Azeotropic and can be accomplished relatively easily Identify alternative separators Select Mass Separating Agent or Entrainer Identify feasible distillate and bottoms product compositions Residue Curve Analysis

16 Pressure Swing to Break Azeotrope
Temp. of Azeotrope vs. Pressure Mole Fraction of Azeotrope

17 Pressure-swing Distillation (Cont’d)
Example: Dehydration of Tetrahydrofuran (THF) T-x-y diagrams for THF and water

18 Other Multi-component Distillation Problems
Multiple Steady States Run same distillation column with same set points but different computational starting point Get Two or More Different Results Top or bottom compositions This is real in that the column will have two different operating conditions! Happens most often with multi component distillation Multiple Solutions Starting Point yD


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