Download presentation
Presentation is loading. Please wait.
Published byStefanie Ritter Modified over 5 years ago
1
Solving Equations with Variables on Both Sides
11-3 Solving Equations with Variables on Both Sides Course 2 Warm Up Problem of the Day Lesson Presentation
2
Solving Equations with Variables on Both Sides
Course 2 11-3 Solving Equations with Variables on Both Sides Warm Up Solve. 1. 6n + 8 – 4n = 20 2. –4w + 16 – 4w = –32 3. 25t – 17 – 13t = 67 4. 4k + 9 n = 6 w = 6 t = 7 3 5 = k = –6 –25
3
Solving Equations with Variables on Both Sides
Course 2 11-3 Solving Equations with Variables on Both Sides Problem of the Day You buy 1 cookie on the first day, 2 on the second day, 3 on the third day, and so on for 10 days. Your friend pays $10 for a cookie discount card and then buys 10 cookies at half price. You both pay the same total amount. What is the cost of one cookie? $0.20
4
Learn to solve equations that have variables on both sides.
Course 2 11-3 Solving Equations with Variables on Both Sides Learn to solve equations that have variables on both sides.
5
Solving Equations with Variables on Both Sides
Course 2 11-3 Solving Equations with Variables on Both Sides Marilyn can rent a video game console for $2.20 per day or buy one for $ The cost of renting a game is $1.99 per day. How many days would Marilyn have to rent both the game and the console to pay as much as she would if she had bought the console and rented the game instead? Problems such as this require you to solve equations that have the same variable on both sides of the equal sign. To solve this kind of problem, you need to get the terms with variables on one side of the equal sign.
6
Solving Equations with Variables on Both Sides
Course 2 11-3 Solving Equations with Variables on Both Sides Additional Example 1: Using Inverse Operations to Group Terms with Variables Group the terms with variables on one side of the equal sign, and simplify. A. 60 – 4y = 8y 60 – 4y = 8y 60 – 4y + 4y = 8y + 4y Add 4y to both sides. 60 = 12y Simplify. B. –5b + 72 = –2b –5b + 72 = –2b –5b + 5b + 72 = –2b + 5b Add 5b to both sides. 72 = 3b Simplify.
7
Solving Equations with Variables on Both Sides
Course 2 11-3 Solving Equations with Variables on Both Sides Try This: Example 1 Group the terms with variables on one side of the equal sign, and simplify. A. 40 – 2y = 6y 40 – 2y = 6y 40 – 2y + 2y = 6y + 2y Add 2y to both sides. 40 = 8y Simplify. B. –8b + 24 = –5b –8b + 24 = –5b –8b + 8b + 24 = –5b + 8b Add 8b to both sides. 24 = 3b Simplify.
8
Additional Example 2A: Solving Equations with Variables on Both Sides
Course 2 11-3 Solving Equations with Variables on Both Sides Additional Example 2A: Solving Equations with Variables on Both Sides Solve. A. 7c = 2c + 55 7c = 2c + 55 7c – 2c = 2c – 2c + 55 Subtract 2c from both sides. 5c = 55 Simplify. 5c = 55 5 Divide both sides by 5. c = 11
9
Additional Example 2B: Solving Equations with Variables on Both Sides
Course 2 11-3 Solving Equations with Variables on Both Sides Additional Example 2B: Solving Equations with Variables on Both Sides Solve. B. 49 – 3m = 4m + 14 49 – 3m = 4m + 14 49 – 3m + 3m = 4m + 3m + 14 Add 3m to both sides. 49 = 7m + 14 Simplify. 49 – 14 = 7m + 14 – 14 Subtract 14 from both sides. 35 = 7m 35 = 7m 7 Divide both sides by 7. 5 = m
10
Additional Example 2C: Solving Equations with Variables on Both Sides
Course 2 11-3 Solving Equations with Variables on Both Sides Additional Example 2C: Solving Equations with Variables on Both Sides C. 2 5 x = 1 x – 12 2 5 1 5 x = x – 12 2 5 x 15 – = 1 – 12 1 5 Subtract x from both sides. 1 5 x –12 = Simplify. 1 5 (5) x = (5)(–12) Multiply both sides by 5. x = –60
11
Solving Equations with Variables on Both Sides
Course 2 11-3 Solving Equations with Variables on Both Sides Try This: Example 2A Solve. A. 8f = 3f + 65 8f = 3f + 65 8f – 3f = 3f – 3f + 65 Subtract 3f from both sides. 5f = 65 Simplify. 5f = 65 5 Divide both sides by 5. f = 13
12
Solving Equations with Variables on Both Sides
Course 2 11-3 Solving Equations with Variables on Both Sides Try This: Example 2B Solve. B. 54 – 3q = 6q + 9 54– 3q = 6q + 9 54 – 3q + 3q = 6q + 3q + 9 Add 3q to both sides. 54 = 9q + 9 Simplify. 54 – 9 = 9q + 9 – 9 Subtract 9 from both sides. 45 = 9q 45 = 9q 9 Divide both sides by 9. 5 = q
13
Solving Equations with Variables on Both Sides
Course 2 11-3 Solving Equations with Variables on Both Sides Try This: Example 2C Solve. C. 2 3 w = 1 w – 9 2 3 1 3 w = w – 9 1 3 2 3 w 13 – = 1 – 9 Subtract w from both sides. 1 3 w –9 = Simplify. 1 3 (3) w = (3)(–9) Multiply both sides by 3. w = –27
14
Additional Example 3: Consumer Math Application
Course 2 11-3 Solving Equations with Variables on Both Sides Additional Example 3: Consumer Math Application Christine can buy a new snowboard for $ She will still need to rent boots for $8.50 a day. She can rent a snowboard and boots for $18.25 a day. How many days would Christine need to rent both the snowboard and the boots to pay as much as she would if she buys the snowboard and rents only the boots for the season?
15
Additional Example 3 Continued
Course 2 11-3 Solving Equations with Variables on Both Sides Additional Example 3 Continued Let d represent the number of days. 18.25d = d Subtract 8.5d from both sides. 18.25d – 8.5d = d – 8.5d 9.75d = 136.5 Simplify. 9.75d = 136.5 Divide both sides by 9.75. 9.75 9.75 d = 14 Christine would need to rent both the snowboard and the boots for 14 days to pay as much as she would have if she had bought the snowboard and rented only the boots.
16
Insert Lesson Title Here
Course 2 11-3 Solving Equations with Variables on Both Sides Insert Lesson Title Here Try This: Example 3 A local telephone company charges $40 per month for services plus a fee of $0.10 a minute for long distance calls. Another company charges $75.00 a month for unlimited service. How many minutes does it take for a person who subscribes to the first plan to pay as much as a person who subscribes to the unlimited plan?
17
Insert Lesson Title Here
Course 2 11-3 Solving Equations with Variables on Both Sides Insert Lesson Title Here Try This: Example 3 Continued Let m represent the number of minutes. 75 = m Subtract 40 from both sides. 75 – 40 = 40 – m 35 = 0.10m Simplify. m 0.10 = Divide both sides by 0.10. 350 = m If you are going to use more than 350 minutes, it will be cheaper to subscribe to the unlimited plan.
18
Insert Lesson Title Here
Course 2 11-3 Solving Equations with Variables on Both Sides Insert Lesson Title Here Lesson Quiz Group the terms with variables on one side of the equal sign, and simplify. 1. 14n = 11n + 81 2. –14k + 12 = –18k Solve. y = –4y – 19 4. – 3n = 81 4k = –12 y = –11 3 4 1 8 x = x – 14 x = 16
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.