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Vectors Day 7 Lyzinski Physics
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# 40, continued
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Day #7
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Plane Problems
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Important things to know:
P: Plane W: Wind G: Ground vPG = vPW + vWG “airspeed” means VPW You can use d = rt in these problems only because a = 0
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vPG = vPW vWG Example: A plane is flying with an airspeed of 400 mph in the northeast direction. Wind is blowing towards the North at 50 mph. Find the velocity of the plane relative to the ground. 45o 400 = 282.84 50 = 436.8 49.6o VPG = mph [E 49.6o N]
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A difficult plane problem
From tonight’s HW 45) vPG = vPW vWG 40o 200 km/h 30 km/h ? 22.98 km/h 19.28 km/h x: y: = km/h 0 – = km/h km/h 22.98 km/h VPG VPG = km/h [W 7.2o S]
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vPG = vPW + vWG vPW = vPG + -vWG [W 6.6o N] ??? 45) rearranging
200 km/h 40o 30 km/h 22.98 km/h 19.28 km/h ??? q x: y: unimportant for this problem [W 6.6o N] 200sin(q) = 22.98 q = sin-1 (22.98/200) = 6.6o
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Tonight’s HW “Days #6 & #7 Relative Velocity HW Problems”
#’s (from the packet) Do Buffa, pg. 101, problems 102, 105
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