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2013 Emissions Inventory Workshop EXAMPLE CALCULATIONS
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General Equation For most emission sources the following equation is used: E = A * EF Where E = Calculated emissions A = Activity or annual process rate EF = Emission factor - determined by the method of calculation Examples sources: AP-42 WebFire Permit 2013 Emissions Inventory Workshop 2
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Process:10-100 mmbtu/hr boiler SCC:10200602 Fuel:Natural Gas Capacity:84 mmbtu/hr Control:Uncontrolled Industrial Boiler – CO & Benzene Calculation 2013 Emissions Inventory Workshop 3
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US EPA CHIEF Website: http://www.epa.gov/ttn/chief/index.html 4
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Industrial Boiler – CO Calculation 2013 Emissions Inventory Workshop 9
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E = A * EF = ??? tons A EF E Convert to tons: 2013 Emissions Inventory Workshop 10
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Industrial Boiler – CO Calculation 2013 Emissions Inventory Workshop 11
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2013 Emissions Inventory Workshop US EPA CHIEF Website: http://www.epa.gov/ttn/chief/index.html 12
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E = A * EF = ??? tons A EF E Convert to tons: 2013 Emissions Inventory Workshop 17
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Industrial Boiler – CO Calculation 2013 Emissions Inventory Workshop 18
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Process: Reciprocating emergency generator SCC:20200102 Fuel:Diesel Capacity:400 hp Pollutant: NOx Factor:604 lbs/1000 gal Control:Uncontrolled Operation:50 hours Activity:500 gal Heat Content:137 mmbtu/1000 gal Emergency Generator – NOx Calculation 2013 Emissions Inventory Workshop 19
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E = A * EF = ??? tons A EF E Convert to tons: 2013 Emissions Inventory Workshop 20
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Process:Surface coating – spray painting SCC:40200101 Pollutant:Xylene, VOC (non-HAP) Paint:Acrylic Red Surface Coating – Xylene & VOC Calculation 2013 Emissions Inventory Workshop 21
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E = A * VOC Content * (Xylene:VOC Ratio) = ??? tons Now, for non-HAP VOC: 2013 Emissions Inventory Workshop 23 VOC (non-HAP ) VOC (non-HAP) = Total VOC ̶ Xylene
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Control Equipment Calculations 2013 Emissions Inventory Workshop 24
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Capture Efficiency: The percentage of air emission that is collected and routed to the control equipment. Most control devices have a 100% capture efficiency. Control Efficiency: The percentage of air pollutant that is removed from the air stream by the control device. Control Efficiency Calculations 2013 Emissions Inventory Workshop 25
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Process:Primary Crushing SCC:30532001 Pollutant:PM10 Control:Water Spraying Stone Quarry – Primary Crushing Calculation 2013 Emissions Inventory Workshop 26
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Stone Quarry – Primary Crushing Calculation 2013 Emissions Inventory Workshop 27
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E = A * EF * (1 – Control Efficiency) = ??? tons A EF E Account for control: Convert to tons: 2013 Emissions Inventory Workshop 28
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Stone Quarry – Primary Crushing Calculation 2013 Emissions Inventory Workshop 29
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Process:Grain handling for feed manufacture SCC:30200801 Activity:10,000 tons Pollutant:PM 10 Factor: 3 lbs/ton Primary Control:Cyclone Secondary Control:Baghouse Two Controls – Grain Handling Calculation 2013 Emissions Inventory Workshop 30
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31 2013 Emissions Inventory Workshop A Complex Situation: Capture Efficiency, Primary Efficiency & Secondary Efficiency
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Capture Device: Hood Therefore, the other 10% is emitted directly to the atmosphere Secondary control device: Baghouse The control equipment removes 98% of PM 10 from the emission stream. Two Controls – Grain Handling Calculation 2013 Emissions Inventory Workshop 32 Primary control device: Cyclone The control equipment removes 80% of PM 10 from the emission stream.
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Total E = Captured E + Uncaptured E = ??? tons 2013 Emissions Inventory Workshop 33 Captured E = A * EF * CE * (1 – PE) * (1 – SE) Uncaptured E = A * EF * (1 – CE)
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Captured E = A * EF * CE * (1 – PE) * (1 – SE) AEF 2013 Emissions Inventory Workshop 34 Account for capture and controls: CE PE SE
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Uncaptured E = E * (1 – CE) Account for all PM 10 emissions: Convert to tons: 2013 Emissions Inventory Workshop 35
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30,000 lbs of PM generated 1 3,000 lbs of PM emitted not captured 2 27,000 lbs of PM captured, sent to cyclone 3 4 Amount to Hopper 27,000 lbs* 0.80 = 21,600 lbs 5 27,000 lbs– 21,600 lbs = 5,400 lbs to the Baghouse Amount emitted to the atmosphere 5,400 lbs – 5,292 lbs = 108 lbs 108 lbs stack emissions + 3,000 lbs not captured, emitted as a fugitive = 3,108 lbs = 1.554 tons 7 6 Amount to Hopper 5,400 lbs * 0.98 = 5,292 lbs 36 2013 Emissions Inventory Workshop
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Other Examples If you would like to see an example calculation for another industry, process, or control equipment not presented today: Please email aei@deq.ok.gov and we will create an example for you. 2013 Emissions Inventory Workshop 37
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ODEQ Emissions Inventory Section Program Manager: Mark Gibbs Mark.Gibbs@deq.ok.gov Emissions Inventory Staff: Michelle Horn Michelle.Horn@deq.ok.gov Justin Milton Justin.Milton@deq.ok.gov Carrie Schroeder Carrie.Schroeder@deq.ok.gov http://www.deq.state.ok.us/aqdnew/emissions/index.htm 2013 Emissions Inventory Workshop 38
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