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Warmup: Decompose the following functions
Lesson: ____ Section: 3.4 The Chain Rule Warmup: Decompose the following functions h(x) = f(g(x)) Outer Function Inner Function Ex. β π₯ = 2π₯+1 Ex. β π₯ = π π₯ Ex. β π₯ = 1 (π₯ 3 +2π₯) 2 u = g(x) = 2x + 1 π π = π u = g(x) = π π = u = g(x) = π π =
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If f and g are differentiable functions, then
πΌπ π’=π π₯ , π¦=π π’ , π‘βππ π¦=π(π π₯ ) A small change in x will generate a small change in u which, in turn, generates a small change in y x u y g(x) f(u) f(g(x)) ππ¦ ππ₯ = ππ¦ ππ’ β ππ’ ππ₯ π ππ₯ π(π π₯ ) πβ² π’ gβ² π₯ The Chain Rule If f and g are differentiable functions, then π ππ₯ π(π π₯ )= π β² (π π₯ )βπβ²(π₯) βThe derivative of a composite function isβ¦ The derivative of the outer function(evaluated at the inner) multiplied by the derivative of the inner.β
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= ππΏ ππ = ππ ππ‘ = ππΏ ππ‘ = ππΏ ππ β ππ ππ‘ = 2 ππ β 3 β βπ = 6 ππ βπ
Suppose the length L, in cm of a steel bar depends on the air temperature, T in ο°C and Temperature depends on time, t, measured in hours. If the length of the bar increases by 2 cm for every degree increase in temperature, and the temperature increases by 3 ο°C per hour, how fast is the length of the bar increasing? What are the units? t T L L depends on T and T depends on t Rate L is increasing with respect to T = ππΏ ππ =2 ππ β Rate T is increasing with respect to t = ππ ππ‘ =3 Β°πΆ βπ Rate L is increasing at with respect to t = ππΏ ππ‘ = ππΏ ππ β ππ ππ‘ = 2 ππ β 3 β βπ = 6 ππ βπ
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Practice these suckas! Ex. π₯ Ex π₯ 2 +5π₯β2 Ex π₯ +2 3
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Ex. 1 π₯ 2 + π₯ 4 Ex. π π₯ 2
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Reviewing the conceptβ¦
Ex. y is a function of π₯. π¦=π π₯ π ππ₯ π₯= π ππ₯ π₯ 2 = π ππ₯ π¦ 2 = 1 Extending the idea a little furtherβ¦ If π¦=π π₯ . π ππ₯ 3π₯π¦ 2 = 3β π ππ₯ π₯ π¦ 2 2π₯ 3β 1 π¦ 2 + π₯ ( ) 2π¦βπ¦β² 2π¦βπ¦β² 3 π¦ 2 +6π₯π¦βπ¦β² You fools want more practice? Try #4, 28, 36, 50, 54, 56 or even 46 Hint: Think of this as π
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π π π π
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Ex. Try d dx x 2 +1 100 again without declaring new variables.
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Try slaying a dragon! Apply the chain rule multiple timesβ¦
Ex. d dx π β π₯ 7 +5
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