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Grab a calculator and graph the following equations:
Starter β Day December 11 Content Objective: SWBAT graph and shift rational functions. Language Objective: SWBAT explain how to determine the vertical and horizontal shifts of a rational function. Grab a calculator and graph the following equations: 1. y= 1 π₯ y= 1 π₯ π¦= 1 π₯ +2
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Each input has a single output βlike a vending machine.
Function Each input has a single output βlike a vending machine. Often written as "π π " where π is the input value. Example: π π =ππ πβππ π=π, π π =π π π π =π
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The domain of π π is EXCEPT values that make the denominator 0.
Rational Function π π = π π+2 A rational expression (a fraction with a polynomial in the numerator and the denominator) that has an equal sign and π π on the other side. The domain of π π is EXCEPT values that make the denominator 0.
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Reciprocal Function π π = 1 π
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Asymptote AΒ lineΒ that a graph approaches (but never reaches) as it heads toward infinity. graph
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Types of Asymptotes Horizontal Asymptotes Vertical Asymptotes
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π indicates a stretch or shrink of the graph.
Rules for Graphing Rational Functions π= π πβπ +π π indicates a stretch or shrink of the graph. If π is negative, the graph reflects over the x-axis. π indicates a horizontal shift (left or right). π indicates a vertical shift (up or down). The line π=βπ is a vertical asymptote. The line π=π is a horizontal asymptote.
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π= π πβπ +π Identify each piece of this equation, and then graph: π¦= 1 π₯β2 +3 π=βπ π=π
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π= π πβπ +π Identify each piece of this equation, and then graph: π¦= 1 π₯β1 +4
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π= π πβπ +π Identify each piece of this equation, and then graph: π¦= 1 π₯β0 β1
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π= π πβπ +π Identify each piece of this equation, and then graph: π¦= 2 π₯ β3
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π= π πβπ +π Write a function that shifts π¦= 1 π₯ up 2 and left 4.
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π= π πβπ +π Write a function that shifts π¦= 1 π₯ down 3 and right 1.
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π= π πβπ +π Write an equation for the following graph:
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LAB Writing Using explain how to determine the vertical and horizontal shifts of a rational function. Assignment Book Section 3.5 No. 1-16, 25, 29, 35 π= π πβπ +π
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