1. Wavelength and Frequency
“nu” “lambda”
c = n l f
c = speed of light (3 x 108 m/s)
= frequency (s-1)
l = wavelength (m)
E = h n
E = energy (Joules or J)
h = Planck’s constant (6.6 x10-34 J/s)
= frequency (s-1)

2. Electromagnetic Spectrum
Frequency & wavelength are inversely proportional
c = 
c: speed of light (3.00  108 m/s)
: wavelength (m, nm, etc.)
: frequency (Hz)
Courtesy Christy Johannesson

3. Electromagnetic Spectrum
EX: Find the frequency of a photon with a wavelength of 434 nm.
GIVEN:
f = ?
 = 434 nm
= 4.34  10-7 m
c = 3.00  108 m/s
WORK:
1 m
1 x 109 nm
f = 3.00  108 m/s
4.34  10-7 m
f = 6.91  1014 Hz
Courtesy Christy Johannesson