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Linear and Quadratic Functions
Chapter 3 Linear and Quadratic Functions
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Section 3 Quadratic Functions and Their Properties
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DAY 1
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Standard form of a quadratic function: f(x) = ax2 + bx + c where a, b, and c are real numbers and a ≠ 0. If a = 0, then ax2 doesn’t exist and you are back to a linear equation. Vertex form of a quadratic function: f(x) = a(x – h)2 + k where a, h, and k are real numbers, a ≠ 0, and (h, k) is the vertex of the graph. *The graph of a quadratic is always a parabola (U shape)*
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Graphing using Transformations You need to use VERTEX FORM to graph using transformations! How can you tell if it is vertex or standard form? If there is a bx term or not Ex. – Which form is it in? f(x) = x2 – 2x + 2 f(x) = (x– 1)2 – 1 f(x) = x2 – 1
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Graph using Transformations f(x) = 2x2 + 8x + 5 If not in vertex form complete the square to put in vertex form to use transformations 1st: group x2 and x, if a ≠ 1 factor it out 2nd: complete the square (b/2)2 3rd: balance the change made
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4th: simplify and factor Now use transformations Basic x2 (-1, 1) (0, 0) (1, 1)
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Properties of Quadratics To determine if it facing up or down: if a = - down, if a = + up All parabolas are symmetrical through the vertex Axis of symmetry x = x-value of vertex Vertex of parabola (h, k) h = -b/2a and k = f(h) Y-intercept: find f(0) [plug in 0 for x] X-intercept: f(x) = 0 and solve for x (factor or quadratic formula)
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SUMMARY – Steps for Graphing a Quadratic Function Option 1 Step 1: Complete the square to write in the form f(x) = a(x – h)2 + k Step 2: Graph the function in stages using transformations Option 2 Step 1: Determine whether the graph opens up or down Step 2: Determine the vertex (-b/2a, f(-b/2a)) and axis of symmetry (-b/2a) Step 3: Determine the y-intercept, f(0). Determine x-intercepts if any If b2 – 4ac > 0, then there are 2 x-intercepts If b2 – 4ac = 0 then the vertex is the x-intercept If b2 – 4ac < 0 then there are no x-intercepts Step 4: Determine an additional point by using the y-intercept and the axis of symmetry
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Example: (#31 pg. 152) (use option 2) f(x) = -x2 – 6x Opens: Vertex: A
Example: (#31 pg. 152) (use option 2) f(x) = -x2 – 6x Opens: Vertex: A.O.S.: Y-int: Domain: X-int: Range:
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DAY 2
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Writing Equations of Quadratics Start with vertex form: Plug in vertex: Use another point to find a:
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Determine if the quadratic has a minimum or maximum value and find that value. f(x) = 2x2 + 12x
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EXIT SLIP
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