1. By: Divya Lobo and Anshul Rangwani
Apollo 13
By: Divya Lobo and Anshul Rangwani

2. What everything Represents
X-axis: It represents the time
Y-axis: Distance from the moon
Equation: Y= 3x^2-78x+500
The graph is decreasing because the longer the time is the shorter the distance from the moon is
y-intercept: (0,500)
The y-intercept represents the original distance from the moon

3. Option 1 would be a disaster
Reasons: Wasting fuel and high chance of death
How did we find out if Apollo 13 went with option 1, they would die?
If you were to graph the equation(3x^2-78x+500) it goes under the x-axis. As stated before, the x-axis is the moon, so if something hits the x-axis that means it hits the moon.
It would be morally incorrect to let them try option one because
there is a big chance of death

4. The steps in math (Calculator)
The first thing we did, was plug in the points, so we can find the equation. The result was a= 3, b = -78, and c equals 500. We then created the equation 3x^2-78x+500, we graphed that and got this >
To find where the rocket was at t=10 sec, we plugged 10 into our equation, and got 20 as a solution. Therefore, the rocket is at 20 km when t=10 sec.

5. Steps in Math Cont’d. 78/6 = 13 3(13^2)-78(13)+500 3(169)-78(13)+500
To find out the minimum point of the quadratic function you use the formula -b/2a and plug that into the equation.
78/6 = 13
3(13^2)-78(13)+500
3(169)-78(13)+500
=-7
minimum point: (13,-7)
Which therefore means that at 13 seconds, Apollo 13 is at its deepest point which is 7 km deep in the moon.
To find out what time Apollo 13 would crash into the moon, you equate 3x^2- 78x+500 to 0, and used the quadratic formula.
(78±√ )/6
(78 ±√84)/6
(78±9.17)/6
x= or x=11.472
Apollo 13 crashes into the moon at sec.