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Unit 4. Day 10.
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Example A: ππππ£π. 4π + 6 = β12 + Alternate form: Familiar form: β6 β6 β18 = 4π 4 4 β 18 4 = 1 π π=β 18 4 β 9 2 β4 1 2 = =
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Example B*: ππππ£π. 8 = 12+ π 4 β12 β12 4 4 π 4 β4 = β16 = π
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Example C: ππππ£π. βπ₯+7 = 3 β7 β7 β π₯ 1 = β4 β1 β1 π₯ = 4
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8βπ¦ = 5 βπβ3 =11 ππππ£π. Example D*: Example E*: Example F*:
β 2 3 π+4=12 Example F*:
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Example D*: ππππ£π. βπβ3 =11 +3 +3 β π 1 = 14 β1 β1 π = β14
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8βπ¦ = 5 8βπ¦ = 5 8 + βπ¦ = 5 π¦ = 3 π¦ = 3 Example E*: ππππ£π. β8 β8 β8 β8
β π¦ 1 = β3 β π¦ 1 = β3 β1 β1 β1 β1 π¦ = 3 π¦ = 3
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β 2 3 π₯ = 1 β β π₯ = 8 β Example F*: β 3 2 β 3 2 β 24 2 β 2 3 π+4=12 β4
Γ· β 2 3 β 2 3 β 2 3 β 24 2 1 8 1 β 3 2 β 24 2 π = β = = β12
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Example G: Write an equation. Then solve the equation.
Mr. Jordan rented one video game and 3 movies for a total of $ The video game cost $4.75 to rent. The movies cost the same amount each to rent. What amount, in dollars, did Mr. Jordan pay to rent each movie? 11.50 4.75 3π + = 4.75+3π=11.50 β4.75 β4.75 3π = 6.75 3 3 π = 2.25
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