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2 Equations, Inequalities, and Applications
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2.5 Formulas and Additional Applications from Geometry
Objectives 1. Solve a formula for one variable, given the values of the other variables. 2. Use a formula to solve an applied problem. 3. Solve problems involving vertical angles and straight angles. 4. Solve a formula for a specified variable.
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Solve a Formula for One Variable
Example 1 Find the value of the remaining variable. P = 2L + 2W; P = 52; L = 8 P = 2L + 2W Check: 2 · · 18 = 52 52 = 2 · 8 + 2W = 52 52 = 52 52 = W –16 –16 36 = 2W 18 = W
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Solve a Formula for One Variable
AREA FORMULAS Triangle A = ½bh Rectangle A = LW Trapezoid A = ½h(b + B) b = base h = height h b L L = Length W = Width W h = height b = small base B = large base b h B
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Use a Formula to Solve an Applied Problem
Example 2 The area of a rectangular garden is 187 in2 with a width of 17 in. What is the length of the garden? A = LW 187 = L · 17 11 = L 17 The length is 11 in. Check: 17 · 11 = 187
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Use a Formula to Solve an Applied Problem
Example 3 Bob is working on a sketch for a new underwater vehicle (UV), shown below. In his sketch, the bottom of the UV is 10 ft long, the top is 8 ft long, and the area is 63 ft2. What is the height of his UV? A = ½h(b + B) The height of the UV is 7ft. 8 63 = ½h(8 + 10) h 10 63 = ½h(18) Check: ½ · 7 · 18 = 63 63 = 9h 7 = h
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Solve Problems Involving Vertical and Straight Angles
2 1 3 4 The figure shows two intersecting lines forming angles that are numbered: , , , and . 1 2 3 4 Angles 1 and 3 lie “opposite” each other. They are called vertical angles. Another pair of vertical angles is 2 and 4.. Vertical angles have equal measures. Now look at angles 1 and 2. When their measures are added, we get the measure of a straight angle, which is 180°. There are three other such pairs of angles: 2 and 3, 3 and 4 and 4 and 1.
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Solve Problems Involving Vertical and Straight Angles
Example 5a Find the measure of each marked angle below. Since the marked angles are vertical angles, they have equal measures. 3x – 4 = 5x – 40 Thus, both angles are (3x – 4)° (5x – 40)° –3x –3x –4 = 2x – 40 3 · 18 – 4 = 50° + 40 + 40 Check: 5 · 18 – 40 = 50° CAUTION Here, the answer was not the value of x! 36 = 2x 18 = x
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Solve Problems Involving Vertical and Straight Angles
Example 5b Find the measure of each marked angle below. Since the marked angles are straight angles, their sum will be 180°. (6x – 10)° (x + 15)° 6x – 10 + x + 15 = 180 Thus, the angles are 7x + 5 = 180 6 · 25 – 10 = 140° and = 40° – 5 – 5 Check: 140° + 40° = 180° 7x = 175 x = 25
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Solve a Formula for a Specified Variable
Example 6 Solve A = ½bh for b. The goal is to get b alone on one side of the equation. 2 · A = ½bh · 2 2A = bh
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