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“Snow and adolescence are the only problems that disappear if you ignore them long enough.”
Earl Wilson
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Notices: HW1 is on-line now and due next Tuesday.
Reading: Chapters 3 and 1
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Stars are exceptionally remote laboratories.
Yet they contain extremely interesting physics. All our information comes from 1 source: light (electromagnetic radiation).
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The 5 basic physical properties of stars:
Luminosity, Mass, Radius (combined as surface gravity), Surface Temperature (Teff) Surface chemical composition (X,Y,Z) Distance, via parallax; Radial velocity via Doppler shift; and Proper motion,
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Luminosities L=4R2T4 Lap=(R2/d2)(T4) Labs=[R2/(d=10pc)2](T4)
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Definition of magnitude
A difference of 5 magnitudes is a brightness ratio of 100. For every 5 magnitudes multiply factors of 100. For every ratio of 100, add 5 magnitudes.
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Distance (3 ways) Method 1) Stellar Parallax: d=1/p for distance in parsecs and parallax angles in arcseconds. 1pc = 3.26ly or 3.086x1016m
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Example: a Cen A has a parallax of p=0.742”, what's its distance?
Method 1) Stellar Parallax: d=1/p for distance in parsecs and parallax angles in arcseconds. 1pc = 3.26ly or 3.086x1016m Example: a Cen A has a parallax of p=0.742”, what's its distance?
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Example: a Cen A has a parallax of p=0.742”, what's its distance?
Method 1) Stellar Parallax: d=1/p for distance in parsecs and parallax angles in arcseconds. 1pc = 3.26ly or 3.086x1016m Example: a Cen A has a parallax of p=0.742”, what's its distance? d=1/p = 1/0.742” = 1.35pc (4.4ly)
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Method 2) Apparent and total luminosity: Lap = L/d2
Distance Method 2) Apparent and total luminosity: Lap = L/d2
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Method 3) in magnitudes. Absolute magnitude (M) is the magnitude an object would be at 10pc.
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How far away is an object with a distance modulus of 15?
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How far away is an object with a distance modulus of 15?
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How far away is an object with a distance modulus of 15?
Note that you pick up a factor of 10 in distance for every 5 magnitudes!
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Method 1: If you can measure the angular size (a) of the star, then
Radius (4 methods) Method 1: If you can measure the angular size (a) of the star, then R=(a/2)d.
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Betelgeuse
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Method 1: If you can measure the angular size (a) of the star, then
Radius (4 methods) Method 1: If you can measure the angular size (a) of the star, then R=(a/2)d. If Betelgeuse has a diameter 700 times that of our Sun, and is at a distance of 197pc, what is a?
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Radius (4 methods) Method 1: R=(a/2)d.
If Betelgeuse has a diameter 700 times that of our Sun, and is at a distance of 197pc, what is a? a= 2R/d. a is unitless, so R and d have to be in the same units, the easiest is probably m. R=700*6.96x108m D = 197*3.09x1016m a= 1.60x10-7 rads = 0.033” (33mas)
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Radius Method 2: (And far more likely!) If you can measure a star's distance: Lap=L/(4pd2) and L=4pR2sT4. If you can get parallax, you can surely get a spectrum, so T is not a problem.
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Radius- Method 3: eclipsing binary Ds=v(t2-t1) or v(t4-t3) and DL=v(t3-t1) or v(t4-t2)
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L from the line widths, which gives luminosity class.
Radius Method 4: Luminosity class and spectral type. R=[L/(4psT4)]1/2 L from the line widths, which gives luminosity class.
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Mass Method 1 (and only!): Binary stars F=GMm/R2
Where M and m are the masses and R is the distance between their centers. However, for non-circular orbits, R → a, which is the semimajor axis. WE WILL DO A COMPLETE BINARY STAR SECTION LATER. FOR NOW, I WILL JUST BUZZ THROUGH THESE.
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General Form of Kepler's 3rd Law.
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Mass What you can determine depends on the type of binary. So a quick review of binary types: 1) Visual Binary 2) Eclipsing Binary 3) Spectroscopic Binary 4) Double-lined (spectrum) Binary
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Visual Binary: One or both stars are seen and proper motion is used to determine binarity.
Where d is distance, i is the inclination and a is the angular distance of 2a.
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Eclipsing binary
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Single-line binary
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Circular orbits make sine waves, eccentric orbits do not.
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Double-lined spectroscopic binary: the motion of both stars is observed.
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Eclipsing, spectroscopic, and double-lined (spectrum) binaries
For all these, you can measure velocities in their spectra. What is d in this case? P?
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Single-lined binaries
Only 1 velocity. The right hand side contains the measurable quantities and is called the mass function. To get actual masses, one mass must be assumed.
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Double-lined binaries
With 2 velocities you get a complete solution. 2 unknowns (M1 and m2) requires 2 equations.
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Double-lined binaries
With 2 velocities you get a complete solution. If v2/v1=3 and M1+m2=12M*, what are M1 and m2?
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Double-lined binaries
With 2 velocities you get a complete solution. If v2/v1=3 and M1+m2=12M*, what are M1 and m2? Since M1=3m2, m2=3 and M1=9.
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Double-lined binaries
With 2 velocities you get a complete solution. In reality there is a sin i in here as well.
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Inclination i Face on is 0o Edge on is 90o
Astrometric binaries use cosine (so cosi=1 for face on) Velocity binaries use sine (so sini=1 for edge on)
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Surface composition: X, Y, Z X + Y + Z = 1
X is the mass fraction of H Y is the mass fraction of He Z is the mass fraction of everything else
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Surface composition: X, Y, Z X + Y + Z = 1
X is the mass fraction of H Y is the mass fraction of He Z is the mass fraction of everything else For the Sun, X=0.73, Y=0.25, Z=0.02
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Surface composition: X, Y, Z X + Y + Z = 1
Composition is determined spectroscopically. WE WILL DO THIS IN MORE DETAIL LATER USING LINE STRENGTHS. For now: Population III stars: By Mass: 75%H, 25%He, 0%Z Population II stars: Z<0.01 (roughly) Population I stars: Z>0.01 (roughly)
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Surface composition: X, Y, Z
For now: Population III stars: By Mass: 75%H, 25%He, 0%Z Population II stars: Z<0.01 (roughly) Population I stars: Z>0.1 (roughly) NOTE: 75%H by mass is 92% by NUMBER of atoms.
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Surface composition: X, Y, Z
What do we actually measure and how do we measure this?
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Surface composition: X, Y, Z Spectral lines provide the # of atoms making a transition, not mass.
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Spectral Classification
O, B, A, F, G, K, M (Oh Boy, Astronomy Faculty Get Killed Monday) Was originally an alphabetic sequence Spectral classification began when Fraunhoffer discovered dark lines in the spectrum of the Sun.
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Spectral Classification
O, B, A, F, G, K, M In 1866, Angelo Secchi created Classes I (with a subtype for stars in Orion), II, and III where I had hydrogen lines, II had calcium and sodium lines, and III had complex bands.
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Spectral Classification
O, B, A, F, G, K, M Secchi classes I, II, and III In the 1890s, a spectroscopic survey added to this classification: I: A, B, C, D II: E, F, G, H, I, K, L III: M Soon ofter these were added? O- spectra with bright lines. P- planetary nebulae. Q- other spectra
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Spectral Classification
O, B, A, F, G, K, M Secchi classes I, II, and III Pickering classification: I: A, B, C, D II: E, F, G, H, I, K, L III: M O- spectra with bright lines. P- planetary nebulae. Q- other spectra In 1901, Annie Jump Cannon simplified it into our current system.
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Spectral Classification
O, B, A, F, G, K, M In 1901, Annie Jump Cannon simplified it into our current system. In the 1920s, Cecilia Payne mathematically showed that a star's spectral class is determined by its temperature.
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