1. 3.91
ANALOGY: If you had $ which I take, then I give you back $35.45, you have lost 72.07% of your money, or have 27%!
2 XI Cl2  2 XCl I2
(0.5000g) (0.2360)
1)The compound lost g of mass as Cl swaps out the iodine. This mass represents the differential between the atomic molar mass if iodine and Cl.
2) The ratio of atomic masses is / = , indicating that Cl is 27.93% as massive as I.
3) The mass difference g represents mass lost as iodine swapped out, this equals (72.07% the mass of the original I in XI3).
4) The total mass of iodine in XI3 is
= g = g I in XI3
mass

2. 1)The compound lost 0. 2640g of mass as Cl swaps out the iodine
1)The compound lost g of mass as Cl swaps out the iodine. This mass represents the differential between the atomic molar mass of iodine and Cl.
2) The ratio of atomic masses is / = , indicating that Cl is 27.93% as massive as I.
3) The mass difference g represents mass lost as iodine swapped out, this equals (72.07% the mass of the original I in XI3).
4) The total mass of iodine in XI3 is
= g = g I in XI3
mass
5) The sample was g – g = g of X
6) g I / g/mol = mol of I in XI3 therefore x is mol X
7) g X/ mol X = g/mol, La.