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Published byLambert Wilkinson Modified over 6 years ago
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Action-Reaction Pairs: Act On Different Bodies
Forces exerted BY a body DO NOT (directly) influence its motion!! Forces exerted ON a body (BY some other body) DO influence its motion!! When discussing forces, use the words “BY” and “ON” carefully.
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Example “Free Body Diagram” for the monitor.
Shows all forces on it, in proper directions. Figure 5.6: (a) When a computer monitor is at rest on a table, the forces acting on the monitor are the normal force n and the gravitational force Fg . The reaction to n is the force Fmt exerted by the monitor on the table. The reaction to Fg is the force FmE exerted by the monitor on the Earth. (b) The free-body diagram for the monitor. Monitor at rest on table. Force of monitor on table ≡ Fmt. Force of table on monitor ≡ Ftm. Ftm keeps monitor from falling. Ftm & Fmt are 3rd Law action-reaction pairs. Forces on monitor are “Normal Force” n & weight Fg. 2nd Law for monitor in vertical direction: ∑Fy = 0 = n - Fg. So, n = Fg = mg. So n = mg. They are equal & in opposite directions, BUT THEY ARE NOT action-reaction pairs (they act on the SAME object, not on different objects!)
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Normal Force 2nd Law ∑F = ma = 0
Suppose object is at rest on table. Does the force of gravity stop? OF COURSE NOT! But, object does not move: 2nd Law ∑F = ma = 0 There must be some other force acting besides gravity (weight) to have ∑F = 0. That force The Normal Force = n “Normal” is math term for perpendicular () n is to the surface & opposite to the weight (in this simple case only!) Caution, the normal force is not always = & opposite to the weight, as we’ll see! n mg
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NO!!! Normal Force Where does the normal force come from?
From the other body!!! Does the normal force ALWAYS equal the weight? NO!!!
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Example m = 10 kg The normal force is NOT always equal to the weight!!
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Example m = 10 kg ∑F = ma FP – mg = ma Note: The normal force
is zero here because the mass isn’t in contact with a surface!
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