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Integration Volumes of revolution.

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Presentation on theme: "Integration Volumes of revolution."β€” Presentation transcript:

1 Integration Volumes of revolution

2 FM Volumes of revolution I: around yAxis
KUS objectives BAT Find Volumes of revolution using Integration; find volumes by rotating around the y-axis Starter:

3 Notes The volume of revolution formed when x=f(y) is rotated around the y-axis between the y- axis, π’š=𝒂 and π’š=𝒃 is given by π‘‰π‘œπ‘™π‘’π‘šπ‘’=πœ‹ π‘Ž 𝑏 π‘₯ 2 𝑑π‘₯ When you use this formula you are integrating with respect to y. So you may need to rearrange functions accordingly

4 WB B1 The region R is bounded by the curve 𝑦= π‘₯βˆ’1 , the y-axis and the horizontal lines 𝑦=1 and 𝑦=3
Find the volume of the solid formed when the region is rotated 2Ο€ radians about the y-axis. Give your answer as a multiple of Ο€ R rearrange 𝑦= π‘₯βˆ’1 to π‘₯= 𝑦 2 +1 π‘£π‘œπ‘™π‘’π‘šπ‘’=πœ‹ 1 3 π‘₯ 2 𝑑𝑦=πœ‹ 𝑦 𝑑𝑦 =πœ‹ 𝑦 4 +2 𝑦 𝑑𝑦 = πœ‹ 𝑦 𝑦 3 +𝑦 3 1 = πœ‹ βˆ’ = πœ‹

5 WB B2 The region R is bounded by the curve π‘₯= 2π‘¦βˆ’1 , the y-axis and the vertical lines y=4 and y = 8
Find the volume of the solid formed when the region is rotated 2Ο€ radians about the y-axis. Give your answer as a multiple of Ο€ π‘₯= 2π‘¦βˆ’1 π‘£π‘œπ‘™π‘’π‘šπ‘’=πœ‹ π‘¦βˆ’ 𝑑𝑦 π‘£π‘œπ‘™π‘’π‘šπ‘’=πœ‹ π‘¦βˆ’1 𝑑𝑦 = πœ‹ 𝑦 2 βˆ’π‘¦ 8 4 = πœ‹ 64βˆ’8 βˆ’πœ‹ 16βˆ’4 =44πœ‹

6 WB B3 The region R is bounded by the curve 𝑦= π‘₯ 2 βˆ’2 the y-axis and the vertical lines 𝑦=1 and 𝑦=3 Find the volume of the solid formed when the region is rotated 2Ο€ radians about the y-axis. Give your answer as a multiple of Ο€ rearrange 𝑦= π‘₯ 2 βˆ’2 to x = (𝑦+2) 1/2 π‘£π‘œπ‘™π‘’π‘šπ‘’=πœ‹ (𝑦+2) 1/ 𝑑𝑦 =πœ‹ 1 3 (2+𝑦) 𝑑𝑦 = πœ‹ 2𝑦 𝑦 =πœ‹ βˆ’2βˆ’ = 8πœ‹

7 WB B4 The region R is bounded by the curve 𝑦= 1 π‘₯ the y-axis and the vertical lines 𝑦=1 and 𝑦=2 Find the volume of the solid formed when the region is rotated 2Ο€ radians about the y-axis. Give your answer as a multiple of Ο€ rearrange 𝑦= 1 π‘₯ to x = 1 𝑦 π‘£π‘œπ‘™π‘’π‘šπ‘’=πœ‹ 𝑦 𝑑𝑦 =πœ‹ 𝑦 2 𝑑𝑦 = πœ‹ βˆ’ 1 𝑦 2 1 = πœ‹ 2

8 WB B5 The region R is bounded by the curve 𝑦= π‘₯ the y-axis and the vertical line 𝑦=2
Find the volume of the solid formed when the region is rotated 2Ο€ radians about the y-axis. rearrange π‘₯= 𝑦 2 π‘£π‘œπ‘™π‘’π‘šπ‘’=πœ‹ 𝑦 𝑑𝑦 π‘£π‘œπ‘™π‘’π‘šπ‘’=πœ‹ 0 2 𝑦 4 𝑑𝑦 = πœ‹ 𝑦 = 32πœ‹ 5 NOW DO Ex 5B

9 One thing to improve is –
KUS objectives BAT Find Volumes of revolution using Integration; find volumes by rotating around the y-axis self-assess One thing learned is – One thing to improve is –

10 END


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