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Six Easy Steps for an ANOVA
1) State the hypothesis 2) Find the F-critical value 3) Calculate the F-value 4) Decision 5) Create the summary table 6) Put answer into words
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Example Want to examine the effects of feedback on self-esteem. Three different conditions -- each have five subjects 1) Positive feedback 2) Negative feedback 3) Control Afterward all complete a measure of self-esteem that can range from 0 to 10.
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Example: Question: Is the type of feedback a person receives significantly (.05) related their self-esteem?
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Results
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Step 1: State the Hypothesis
H1: The three population means are not all equal H0: pos = neg = cont
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Step 2: Find F-Critical Step 2.1
Need to first find dfbetween and dfwithin dfbetween = k (k = number of groups) dfwithin = N - k (N = total number of observations) dftotal = N - 1 Check yourself dftotal = dfbetween + dfwithin
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Step 2: Find F-Critical Step 2.1
Need to first find dfbetween and dfwithin dfbetween = (k = number of groups) dfwithin = (N = total number of observations) dftotal = 14 Check yourself 14 =
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Step 2: Find F-Critical Step 2.2 Look up F-critical using table F
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Step 2: Find F-Critical Step 2.2 Look up F-critical using table F
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Step 3: Calculate the F-value
Has 4 Sub-Steps 3.1) Calculate the needed ingredients 3.2) Calculate the SS 3.3) Calculate the MS 3.4) Calculate the F-value
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Step 3.1: Ingredients X X2 Tj2 N n
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Step 3.1: Ingredients
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X X = 85 Xp = 40 Xn = 25 Xc = 20
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X2 X = 85 X2 = 555 Xp = 40 Xn = 25 Xc = 20 X2n = 135 X2c = 90
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T2 = (X)2 for each group X = 85 X2 = 555 Xp = 40 Xn = 25 Xc = 20
T2n = 625 T2c = 400 T2p = 1600
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Tj2 X = 85 X2 = 555 Tj2 = 2625 Xp = 40 Xn = 25 Xc = 20
T2n = 625 T2c = 400 T2p = 1600
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N X = 85 X2 = 555 Tj2 = 2625 N = 15 Xp = 40 Xn = 25 Xc = 20
T2n = 625 T2c = 400 T2p = 1600
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n X = 85 X2 = 555 Tj2 = 2625 N = 15 n = 5 Xp = 40 Xn = 25
Xc = 20 X2n = 135 X2c = 90 X2p = 330 T2n = 625 T2c = 400 T2p = 1600
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Step 3.2: Calculate SS SStotal X = 85 X2 = 555 Tj2 = 2625 N = 15
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Step 3.2: Calculate SS 85 73.33 555 15 SStotal X = 85 X2 = 555
Tj2 = 2625 N = 15 n = 5 Step 3.2: Calculate SS SStotal 85 73.33 555 15
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Step 3.2: Calculate SS SSWithin X = 85 X2 = 555 Tj2 = 2625 N = 15
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Step 3.2: Calculate SS 2625 30 555 5 SSWithin X = 85 X2 = 555
Tj2 = 2625 N = 15 n = 5 Step 3.2: Calculate SS SSWithin 2625 30 555 5
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Step 3.2: Calculate SS SSBetween X = 85 X2 = 555 Tj2 = 2625 N = 15
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Step 3.2: Calculate SS 43.33 2625 85 5 15 SSBetween X = 85 X2 = 555
Tj2 = 2625 N = 15 n = 5 Step 3.2: Calculate SS SSBetween 43.33 2625 85 5 15
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Step 3.2: Calculate SS Check! SStotal = SSBetween + SSWithin
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Step 3.2: Calculate SS Check! 73.33 =
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Step 3.3: Calculate MS
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Step 3.3: Calculate MS 43.33 21.67 2
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Calculating this Variance Ratio
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Step 3.3: Calculate MS 30 2.5 12
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Step 3.4: Calculate the F value
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Step 3.4: Calculate the F value
21.67 8.67 2.5
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Step 4: Decision If F value > than F critical
Reject H0, and accept H1 If F value < or = to F critical Fail to reject H0
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Step 4: Decision If F value > than F critical
Reject H0, and accept H1 If F value < or = to F critical Fail to reject H0
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Step 5: Create the Summary Table
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Step 6: Put answer into words
Question: Is the type of feedback a person receives significantly (.05) related their self-esteem? H1: The three population means are not all equal The type of feedback a person receives is related to their self-esteem
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Practice You are interested in comparing the performance of three models of cars. Random samples of five owners of each car were used. These owners were asked how many times their car had undergone major repairs in the last 2 years.
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Results
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Practice Is there a significant (.05) relationship between the model of car and repair records?
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Step 1: State the Hypothesis
H1: The three population means are not all equal H0: V = F = G
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Step 2: Find F-Critical Step 2.1
Need to first find dfbetween and dfwithin Dfbetween = (k = number of groups) dfwithin = (N = total number of observations) dftotal = 14 Check yourself 14 =
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Step 2: Find F-Critical Step 2.2
Look up F-critical using table F on pages F (2,12) = 3.88
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Step 3.1: Ingredients X = 60 X2 = 304 Tj2 = 1400 N = 15 n = 5
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Step 3.2: Calculate SS SStotal X = 60 X2 = 304 Tj2 = 1400 N = 15
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Step 3.2: Calculate SS 60 64 304 15 SStotal X = 60 X2 = 304
Tj2 = 1400 N = 15 n = 5 Step 3.2: Calculate SS SStotal 60 64 304 15
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Step 3.2: Calculate SS SSWithin X = 60 X2 = 304 Tj2 = 1400 N = 15
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Step 3.2: Calculate SS 1400 24 304 5 SSWithin X = 60 X2 = 304
Tj2 = 1400 N = 15 n = 5 Step 3.2: Calculate SS SSWithin 1400 24 304 5
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Step 3.2: Calculate SS SSBetween X = 60 X2 = 304 Tj2 = 1400 N = 15
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Step 3.2: Calculate SS 40 1400 60 5 15 SSBetween X = 60 X2 = 304
Tj2 = 1400 N = 15 n = 5 Step 3.2: Calculate SS SSBetween 40 1400 60 5 15
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Step 3.2: Calculate SS Check! SStotal = SSBetween + SSWithin
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Step 3.2: Calculate SS Check! 64 =
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Step 3.3: Calculate MS
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Step 3.3: Calculate MS 40 20 2
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Calculating this Variance Ratio
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Step 3.3: Calculate MS 24 2 12
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Step 3.4: Calculate the F value
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Step 3.4: Calculate the F value
20 10 2
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Step 4: Decision If F value > than F critical
Reject H0, and accept H1 If F value < or = to F critical Fail to reject H0
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Step 4: Decision If F value > than F critical
Reject H0, and accept H1 If F value < or = to F critical Fail to reject H0
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Step 5: Create the Summary Table
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Step 6: Put answer into words
Question: Is there a significant (.05) relationship between the model of car and repair records? H1: The three population means are not all equal There is a significant relationship between the type of car a person drives and how often the car is repaired
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Conceptual Understanding
Complete the above table for an ANOVA having 3 levels of the independent variable and n = 20. Test for significant at .05.
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Conceptual Understanding
Fcrit = 3.18 Complete the above table for an ANOVA having 3 levels of the independent variable and n = 20. Test for significant at .05. Fcrit (2, 57) = 3.15
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Conceptual Understanding
Distinguish between: Between-group variability and within-group variability What do they measure? How do they work together?
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Conceptual Understanding
Distinguish between: Between-group variability and within-group variability Between concerns the differences between the mean scores in various groups Within concerns the variability of scores within each group
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Between and Within Group Variability
Between-group variability Within-group variability
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Between and Within Group Variability
sampling error + effect of variable sampling error
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Conceptual Understanding
Under what circumstance will the F ratio, over the long run, approach 1.00? Under what circumstances will the F ratio be greater than 1.00?
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Conceptual Understanding
Under what circumstance will the F ratio, over the long run, approach 1.00? Under what circumstances will the F ratio be greater than 1.00? F ratio will approach 1.00 when the null hypothesis is true F ratio will be greater than 1.00 when the null hypothesis is not true
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Conceptual Understanding
Without computing the SS within, what must its value be? Why?
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Conceptual Understanding
The SS within is 0. All the scores within a group are the same (i.e., there is NO variability within groups)
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