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L1 Shortest Path Queries among Polygonal Obstacles in the Plane

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Presentation on theme: "L1 Shortest Path Queries among Polygonal Obstacles in the Plane"— Presentation transcript:

1 L1 Shortest Path Queries among Polygonal Obstacles in the Plane
Danny Z. Chen1 and Haitao Wang2 1University of Notre Dame 2Utah State University

2 Shortest paths among polygonal obstacles
Input: A set of h polygonal obstacles with a total of n vertices, and two points s and t Output: A shortest path from s to t that avoids the obstacles t free space s obstacle

3 Shortest path queries Build a shortest path map (SPM), such that for any query point t, compute the shortest path from s to t t t t s obstacle

4 Our problem: the L1 version
L1 shortest path: a path with minimum L1 distance The path can be arbitrarily polygonal But the distance is measured by L1 metric vertical distance e horizontal distance The L1 distance of e = the horizontal distance + the vertical distance

5 Previous work (a single shortest path)
Studied by Clarkson, Lee, Kapoor, Widmayer, Wu, Wong, Vaidya, Chen, Klenk, Tu, Inkulu, etc. O(nlogn) time and O(n) space, Mitchell 92’ O(T+n+hlogh) time and O(n) space, Chen and Wang 11’ T = O(n+hlog1+εh) : the time for triangulating the free space, Bar-Yehuda and Chazelle, 94’

6 Previous work and our new result (shortest path queries)
Mitchell 92’ Time for building an SPM: O(nlogn) Space: O(n) Query time: O(k+logn) k: the number of edges of the path Our new result (in this talk) Time for building an SPM: O(T+n+hlogh) O(n+hlog h) time, if a triangulation is given

7 More… Our algorithm runs in Θ(T) time Why?
building an SPM is equivalent to triangulating the free space Why? Lower bound: T=Ω(n+hlogh) Given a triangulation, build an SPM in O(n+hlogh) time Given an SPM obtain a triangulation in O(n) time

8 Our approach (previous work)
Reduce the problem to the convex case where all obstacles are convex Solve the convex case O(n+hlogh) time and O(n) space an SPM is also built Open: Building an SPM for the general (non-convex) problem the key: solving a sub-problem optimally

9 The key sub-problem a shortest path from s to t s c r t P
The green region is the Voronoi region of r, denoted by VR(r) d

10 The key sub-problem Each site has a weight : the length of
the L1 shortest path from s to it c Goal: Compute the L1 geodesic Voronoi diagram for the sites that influence P only through cd, or compute the Voronoi region for each site P N: the number of vertices of P M: the number of red sites d

11 Difficulties How to handle the interactions of the bisectors? c
Goal: building the SPM in O(n+hlogh) time Goal for solving the sub-problem: O(M+N) time P d

12 The standard approaches
O((N+M)log(N+M))  overall O(nlogn) time Continuous Dijkstra paradigm Sweeping Divide-and-conquer Our approach: incremental O(N+M)

13 Bisectors of two weighted sites
middle segment A bisector: a middle segment, and two half-lines, vertical or horizontal

14 Our algorithm Order the sites r1, r2, … rm by
the sub-segments of cd contained in their cells from c to d r1 c r2 r3 P r4 d

15 Obtaining the rays r1 c r2 Middle segments must appear in the Voronoi
diagram r3 P r4 r5 d

16 Preprocessing c sites for the yellow region r2 p q
sites for the brown region r3 P d

17 Processing the rays incrementally
VR(r1) r1 c Vertical rays are stored in a stack r2 r3 VR(r3) P r4 r5 d

18 Processing the rays incrementally
VR(r1) r1 c r2 r3 VR(r3) r4 P r5 d

19 Processing the rays incrementally
VR(r1) r1 c Vertical rays are stored in a stack r2 r3 r4 P r5 d

20 Processing the rays incrementally
VR(r1) r1 c r2 r3 r4 VR(r4) P r5 d

21 Processing the rays incrementally
VR(r1) r1 c r2 r3 r4 VR(r4) P VR(r3) r5 d

22 Processing the rays incrementally
VR(r1) r1 c r2 r3 VR(r2) r4 P r5 VR(r3) d

23 Implementation Data structures: linked lists, a stack, vertical and horizontal visibility decompositions of P horizontal visibility decomposition vertical visibility decomposition

24 Conclusions Build an L1 shortest path map in Θ(T+n+hlogh) time
Build a special L1 weighted geodesic Voronoi diagram Linear time

25 Thank You


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