Presentation is loading. Please wait.

Presentation is loading. Please wait.

a linear transformation from V into V

Similar presentations


Presentation on theme: "a linear transformation from V into V"— Presentation transcript:

1 a linear transformation from V into V
a group a vector space V a linear transformation from V into V a review of the whole course in one example Pamela Leutwyler

2 G is a commutative group.
& a b c d e f g h i

3 & a b c d e f g h i G is a commutative group.
Note that the table has closure. x&y is a member of G for ALL x and y. ie: every entry on the table belongs to G. & a b c d e f g h i

4 & a b c d e f g h i G is a commutative group. i is the identity.
ix = x for ALL x and xi = x for ALL x. & a b c d e f g h i

5 & a b c d e f g h i G is a commutative group. i is the identity.
a is the inverse of f . & a b c d e f g h i af = I and fa = i

6 & a b c d e f g h i G is a commutative group. i is the identity.
a is the inverse of f . b is the inverse of c . d is the inverse of g . h is the inverse of e .

7 & a b c d e f g h i G is a commutative group. (b&h)&d b&(h&d)
Here is one example demonstrating associativity. Remember: (x&y)&z = x&(y&z) for ALL z,y,z in G & a b c d e f g h i (b&h)&d b&(h&d)

8 & a b c d e f g h i G is a commutative group. (b&h)&d b&(h&d) (a)&d
Here is one example demonstrating associativity. Remember: (x&y)&z = x&(y&z) for ALL z,y,z in G & a b c d e f g h i (b&h)&d b&(h&d) (a)&d b&(b)

9 & a b c d e f g h i G is a commutative group. c c (b&h)&d b&(h&d)
Here is one example demonstrating associativity. Remember: (x&y)&z = x&(y&z) for ALL z,y,z in G & a b c d e f g h i (b&h)&d b&(h&d) (a)&d b&(b) c c

10 & a b c d e f g h i G is a commutative group. i is the identity.
a is the inverse of f . b is the inverse of c . d is the inverse of g . h is the inverse of e . H = { a, f, i } is a subgroup. Note that it has closure.

11 & a b c d e f g h i G is a commutative group. H = { a, f, i }
is a subgroup. Note that it has closure.

12 & a f i G is a commutative group. H = { a, f, i } is a subgroup.
Note that it has closure.

13 & a b c d e f g h i G is a commutative group. H = { a, f, i }
is a subgroup. & a b c d e f g h i

14 & a b c d e f g h i G is a commutative group. H = { a, f, i }
is a subgroup. & a b c d e f g h i add b to every member of H to form a COSET of H. { a, f, i } b+

15 & a b c d e f g h i G is a commutative group. H = { a, f, i }
is a subgroup. & a b c d e f g h i add b to every member of H to form a COSET of H. { a, f, i } b+ { g, e, b }

16 & a b c d e f g h i G is a commutative group. H = { a, f, i }
is a subgroup. & a b c d e f g h i The cosets of H are: { g, e, b } { h, d, c }

17 G is a commutative group.
& a b c d e f g h i

18 & a b c d e f g h i G is a commutative group.
We can build a VECTOR SPACE using G as our set of vectors, and arithmetic mod 3 as our field of scalars. & a b c d e f g h i

19 & a b c d e f g h i + 1 2 x . a b c d e f g h i 1 2

20 let’s verify some vector space properties:
& a b c d e f g h i + 1 2 x . a b c d e f g h i 1 2 let’s verify some vector space properties: 2(g&b) (2g)&(2b)

21 let’s verify some vector space properties:
& a b c d e f g h i + 1 2 x . a b c d e f g h i 1 2 let’s verify some vector space properties: 2(g&b) (2g)&(2b) d & c 2  h

22 = let’s verify some vector space properties: 2(g&b) (2g)&(2b) d & c
h i + 1 2 x . a b c d e f g h i 1 2 let’s verify some vector space properties: = 2(g&b) (2g)&(2b) d & c 2  h e e

23 let’s verify some vector space properties:
& a b c d e f g h i + 1 2 x . a b c d e f g h i 1 2 let’s verify some vector space properties:

24 let’s verify some vector space properties:
& a b c d e f g h i + 1 2 x . a b c d e f g h i 1 2 let’s verify some vector space properties: ( )  d ( 2 d ) + ( 2  d ) 1  d g + g d d

25 let’s verify some vector space properties:
& a b c d e f g h i + 1 2 x . a b c d e f g h i 1 2 let’s verify some vector space properties:

26 let’s verify some vector space properties:
& a b c d e f g h i + 1 2 x . a b c d e f g h i 1 2 let’s verify some vector space properties: ( 2 x 2 )  a 2  ( 2  a ) 1  a 2  f a a

27 v we will name this vector space V & a b c d e f g h i . + 1 2 x a b c
1 2 x . a b c d e f g h i 1 2 we will name this vector space V

28 v { a, b } is a basis for V 0a + 0b = i 1a + 2b = h
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V 0a + 0b = i 1a + 2b = h Examine all linear combinations of a and b to the right. Every vector in V is a linear combination of a and b. 0a + 1b = b 2a + 0b = f 0a + 2b = c 2a + 1b = e 1a + 0b = a 2a + 2b = d 1a + 1b = g

29 v { a, b } is a basis for V 0a + 0b = i 1a + 2b = h
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V 0a + 0b = i 1a + 2b = h Examine all linear combinations of a and b to the right. Every vector in V is a linear combination of a and b. 0a + 1b = b 2a + 0b = f 0a + 2b = c 2a + 1b = e 1a + 0b = a 2a + 2b = d The only linear combination to produce i is trivial. 1a + 1b = g

30 v { a, b } is a basis for V dim V = 2 {a,b} spans V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 dim V = 2 {a,b} spans V {a,b} is independent { a, b } is a basis for V 0a + 0b = i 1a + 2b = h Examine all linear combinations of a and b to the right. Every vector in V is a linear combination of a and b. 0a + 1b = b 2a + 0b = f 0a + 2b = c 2a + 1b = e 1a + 0b = a 2a + 2b = d The only linear combination to produce i is trivial. 1a + 1b = g

31 v T is a linear transformation from V into V & a b c d e f g h i .
+ 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h 0a + 0b = i T(b)=e 0a + 1b = b T(c)=h 0a + 2b = c T(d)=i 1a + 0b = a T(e)=h 1a + 1b = g T(f)=e 1a + 2b = h 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

32 v T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h 0a + 0b = i the NULL SPACE of T = { d, g, i } T(b)=e 0a + 1b = b T(c)=h 0a + 2b = c T(d)=i 1a + 0b = a T(e)=h 1a + 1b = g T(f)=e 1a + 2b = h 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

33 v T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h 0a + 0b = i the NULL SPACE of T = { d, g, i } T(b)=e 0a + 1b = b T(c)=h 0a + 2b = c T(d)=i 1a + 0b = a T(e)=h 1a + 1b = g the RANGE of T = { h, e, i } T(f)=e 1a + 2b = h 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

34 v T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h 0a + 0b = i the NULL SPACE of T = { d, g, i } T(b)=e 0a + 1b = b 0d = i d = d d = g { d } is a basis for the null space T(c)=h 0a + 2b = c T(d)=i 1a + 0b = a T(e)=h 1a + 1b = g the RANGE of T = { h, e, i } T(f)=e 1a + 2b = h 0h = i h = h h = e { h } is a basis for the range 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

35 v T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h 0a + 0b = i the NULL SPACE of T = { d, g, i } T(b)=e 0a + 1b = b 0d = i d = d d = g { d } is a basis for the null space T(c)=h 0a + 2b = c T(d)=i 1a + 0b = a T(e)=h 1a + 1b = g the RANGE of T = { h, e, i } T(f)=e 1a + 2b = h 0h = i h = h h = e { h } is a basis for the range 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i dim domain = dim null space + dim range

36 v T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h 0a + 0b = i the NULL SPACE of T = { d, g, i } T(b)=e 0a + 1b = b T(c)=h Note that {d,g,i} is a subspace 0a + 2b = c T(d)=i 1a + 0b = a T(e)=h 1a + 1b = g T(f)=e 1a + 2b = h 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

37 v T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h 0a + 0b = i the NULL SPACE of T = { d, g, i } T(b)=e 0a + 1b = b T(c)=h Note that {d,g,i} is a subspace (subgroup) 0a + 2b = c T(d)=i 1a + 0b = a Note the cosets of the null space. Every element within a given coset has the same image. T(e)=h 1a + 1b = g T(f)=e 1a + 2b = h 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

38 v T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h to find the MATRIX for T relative to the basis {a, b} : 0a + 0b = i T(b)=e 0a + 1b = b T(c)=h 0a + 2b = c T(d)=i 1a + 0b = a T(e)=h 1a + 1b = g T(f)=e 1a + 2b = h 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

39 v T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h to find the MATRIX for T relative to the basis {a, b} : 0a + 0b = i T(b)=e 0a + 1b = b first column is T(a) = h = 1a + 2 b T(c)=h 0a + 2b = c T(d)=i 1a + 0b = a T(e)=h 1a + 1b = g T(f)=e 1a + 2b = h 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

40 v T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h to find the MATRIX for T relative to the basis {a, b} : 0a + 0b = i T(b)=e 0a + 1b = b first column is T(a) = h = 1a + 2 b T(c)=h 0a + 2b = c T(d)=i 1a + 0b = a second column is T(b) = e = 2a + 1 b T(e)=h 1a + 1b = g T(f)=e 1a + 2b = h 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

41 v ( 1 2 ) T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h to find the MATRIX for T relative to the basis {a, b} : 0a + 0b = i T(b)=e 0a + 1b = b first column is T(a) = h = 1a + 2 b T(c)=h 0a + 2b = c T(d)=i 1a + 0b = a second column is T(b) = e = 2a + 1 b T(e)=h 1a + 1b = g T(f)=e 1a + 2b = h ( 1 2 ) 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

42 v ( 1 2 ) ( 2 ) 1 T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h to find the MATRIX for T relative to the basis {a, b} : 0a + 0b = i T(b)=e ( 2 ) 1 0a + 1b = b T(c)=h verify: e = 0a + 2b = c T(d)=i 1a + 0b = a T(e)=h 1a + 1b = g T(f)=e 1a + 2b = h ( 1 2 ) 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

43 & a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h to find the MATRIX for T relative to the basis {a, b} : 0a + 0b = i T(b)=e ( 2 ) 1 0a + 1b = b T(c)=h verify: e = 0a + 2b = c T(d)=i 1a + 0b = a T(e)=h 1a + 1b = g T(f)=e 1a + 2b = h ( 1 2 ) ( 2 ) 1 ( 1 ) 2 2a + 0b = f T(g)=i = = h 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

44 v ( 1 2 ) T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h to find the MATRIX for T relative to the basis {a, b} : 0a + 0b = i T(b)=e 0a + 1b = b T(c)=h 0a + 2b = c T(d)=i 1a + 0b = a T(e)=h 1a + 1b = g T(f)=e 1a + 2b = h ( 1 2 ) 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

45 v ( 1 2 ) ( 2 ) ( 2 ) ( ) T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h to find the MATRIX for T relative to the basis {a, b} : 0a + 0b = i T(b)=e ( 2 ) 0a + 1b = b T(c)=h verify: d = 0a + 2b = c T(d)=i 1a + 0b = a T(e)=h 1a + 1b = g T(f)=e 1a + 2b = h ( 1 2 ) ( 2 ) ( ) 2a + 0b = f T(g)=i = = i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

46 v ( 1 2 ) T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h to find the MATRIX for T relative to the basis {a, b} : 0a + 0b = i T(b)=e 0a + 1b = b T(c)=h Check some other cases. This matrix times the coordinates of a vector v relative to {a,b} will give the coordinates of T v relative to {a,b} . 0a + 2b = c T(d)=i 1a + 0b = a T(e)=h 1a + 1b = g T(f)=e 1a + 2b = h ( 1 2 ) 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

47 v T is a linear transformation from V into V
& a b c d e f g h i v + 1 2 x . a b c d e f g h i 1 2 { a, b } is a basis for V T is a linear transformation from V into V T(a)=h to find the MATRIX for T relative to the basis {a, b} : 0a + 0b = i T(b)=e ( 1 2 ) 0a + 1b = b T(c)=h 0a + 2b = c T(d)=i 1a + 0b = a T is not the only linear transformation from V into V. Since every linear transformation corresponds to a 2x2 matrix, you can create a different example by choosing a different set of 4 scalars to build the matrix. For example defines another linear transformation. T(e)=h 1a + 1b = g T(f)=e 1a + 2b = h 2a + 0b = f T(g)=i 2a + 1b = e T(h)=e 2a + 2b = d T(i)=i

48 V into V is called a LINEAR ALGEBRA.
& a b c d e f g h i + 1 2 x . a b c d e f g h i 1 2 The set of ALL linear transformations ( ie: 2x2 matrices of scalars) from V into V is called a LINEAR ALGEBRA. Since there are 3 scalars in this system, there are 3x3x3x3 = 81 ways to form a 2x2 matrix and there are 81 different linear transformations from V into V.


Download ppt "a linear transformation from V into V"

Similar presentations


Ads by Google