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Calculus BC AP/Dual, Revised ยฉ2018

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1 Calculus BC AP/Dual, Revised ยฉ2018
Polar Area Day 4 Section 10.5C Calculus BC AP/Dual, Revised ยฉ2018 4/24/ :25 PM ยง10.5C: Polar AP Practice

2 Review Find the first derivative of ๐’“=๐Ÿ+ ๐œ๐จ๐ฌ ๐œฝ 4/24/2019 11:25 PM
ยง10.5C: Polar AP Practice

3 Example 1 Find the second derivative of ๐’“=๐Ÿ+ ๐œ๐จ๐ฌ ๐œฝ given that ๐’… ๐’…๐’š ๐’…๐’™ = ๐Ÿ‘(๐Ÿ+ ๐œ๐จ๐ฌ ๐œฝ) ๐ฌ๐ข๐ง ๐œฝ +๐Ÿ ๐ฌ๐ข๐ง ๐œฝ ๐œ๐จ๐ฌ ๐œฝ ๐Ÿ 4/24/ :25 PM ยง10.5C: Polar AP Practice

4 Example 1 Find the second derivative of ๐’“=๐Ÿ+ ๐œ๐จ๐ฌ ๐œฝ given that ๐’… ๐’…๐’š ๐’…๐’™ = ๐Ÿ‘(๐Ÿ+ ๐œ๐จ๐ฌ ๐œฝ) ๐ฌ๐ข๐ง ๐œฝ +๐Ÿ ๐ฌ๐ข๐ง ๐œฝ ๐œ๐จ๐ฌ ๐œฝ ๐Ÿ 4/24/ :25 PM ยง10.5C: Polar AP Practice

5 Your Turn Find the second derivative of ๐’“= ๐ฌ๐ข๐ง ๐œฝ given that ๐’… ๐’…๐’š ๐’…๐’™ = ๐Ÿ ๐ฌ๐ข๐ง ๐œฝ ๐œ๐จ๐ฌ ๐œฝ ๐œ๐จ๐ฌ ๐Ÿ ๐œฝโˆ’ ๐ฌ๐ข๐ง ๐Ÿ ๐œฝ 4/24/ :25 PM ยง10.5C: Polar AP Practice

6 Example 2 Find the area between the two spirals of ๐’“=๐œฝ and ๐’“=๐Ÿ๐œฝ for ๐ŸŽโ‰ค๐œฝโ‰ค๐Ÿ๐…. 4/24/ :25 PM ยง10.5C: Polar AP Practice

7 Example 3 The graphs of the polar curves of ๐’“=๐Ÿ and ๐’“=๐Ÿ‘+๐Ÿ ๐œ๐จ๐ฌ ๐œฝ are shown. The curves intersect when ๐œฝ= ๐Ÿ๐… ๐Ÿ‘ and ๐œฝ= ๐Ÿ’๐… ๐Ÿ‘ . (calc allowed) Let ๐‘น be the region that is inside of the graph of ๐’“=๐Ÿ and also inside the graph of ๐’“=๐Ÿ‘+๐Ÿ ๐œ๐จ๐ฌ ๐œฝ , as shaded in the figure. Find the area. A particle is moving with nonzero velocity along the polar curve given by ๐’“=๐Ÿ‘+๐Ÿ ๐œ๐จ๐ฌ ๐œฝ has position of ๐’™ ๐’• ,๐’š ๐’• at time ๐’•, with ๐œฝ=๐ŸŽ with ๐’•=๐ŸŽ. This particle moves along the curve so that ๐’…๐’š ๐’…๐’• = ๐’…๐’“ ๐’…๐œฝ . Find the value of ๐’…๐’“ ๐’…๐’• at ๐œฝ= ๐… ๐Ÿ‘ and interpret answer in terms of motion of the particle. For the particle described in part (b), ๐’…๐’š ๐’…๐’• = ๐’…๐’“ ๐’…๐œฝ , find the value of ๐’…๐’š ๐’…๐’• at ๐œฝ= ๐… ๐Ÿ‘ and interpret answer in terms of motion of the particle. 4/24/ :25 PM ยง10.5C: Polar AP Practice

8 Example 3a The graphs of the polar curves of ๐’“=๐Ÿ and ๐’“=๐Ÿ‘+๐Ÿ ๐œ๐จ๐ฌ ๐œฝ are shown. The curves intersect when ๐œฝ= ๐Ÿ๐… ๐Ÿ‘ and ๐œฝ= ๐Ÿ’๐… ๐Ÿ‘ . Let ๐‘น be the region that is inside of the graph of ๐’“=๐Ÿ and also inside the graph of ๐’“=๐Ÿ‘+๐Ÿ ๐œ๐จ๐ฌ ๐œฝ , as shaded in the figure. Find the area. 4/24/ :25 PM ยง10.5C: Polar AP Practice

9 Example 3a The graphs of the polar curves of ๐’“=๐Ÿ and ๐’“=๐Ÿ‘+๐Ÿ ๐œ๐จ๐ฌ ๐œฝ are shown. The curves intersect when ๐œฝ= ๐Ÿ๐… ๐Ÿ‘ and ๐œฝ= ๐Ÿ’๐… ๐Ÿ‘ . Let ๐‘น be the region that is inside of the graph of ๐’“=๐Ÿ and also inside the graph of ๐’“=๐Ÿ‘+๐Ÿ ๐œ๐จ๐ฌ ๐œฝ , as shaded in the figure. Find the area. 4/24/ :25 PM ยง10.5C: Polar AP Practice

10 Example 3b The graphs of the polar curves of ๐’“=๐Ÿ and ๐’“=๐Ÿ‘+๐Ÿ ๐œ๐จ๐ฌ ๐œฝ are shown. The curves intersect when ๐œฝ= ๐Ÿ๐… ๐Ÿ‘ and ๐œฝ= ๐Ÿ’๐… ๐Ÿ‘ . (b) A particle is moving with nonzero velocity along the polar curve given by ๐’“=๐Ÿ‘+๐Ÿ ๐œ๐จ๐ฌ ๐œฝ has position of ๐’™ ๐’• ,๐’š ๐’• at time ๐’•, with ๐œฝ=๐ŸŽ with ๐’•=๐ŸŽ. This particle moves along the curve so that ๐’…๐’š ๐’…๐’• = ๐’…๐’“ ๐’…๐œฝ . Find the value of ๐’…๐’“ ๐’…๐’• at ๐œฝ= ๐… ๐Ÿ‘ and interpret answer in terms of motion of the particle. 4/24/ :25 PM ยง10.5C: Polar AP Practice

11 Example 3b The graphs of the polar curves of ๐’“=๐Ÿ and ๐’“=๐Ÿ‘+๐Ÿ ๐œ๐จ๐ฌ ๐œฝ are shown. The curves intersect when ๐œฝ= ๐Ÿ๐… ๐Ÿ‘ and ๐œฝ= ๐Ÿ’๐… ๐Ÿ‘ . (b) A particle is moving with nonzero velocity along the polar curve given by ๐’“=๐Ÿ‘+๐Ÿ ๐œ๐จ๐ฌ ๐œฝ has position of ๐’™ ๐’• ,๐’š ๐’• at time ๐’•, with ๐œฝ=๐ŸŽ with ๐’•=๐ŸŽ. This particle moves along the curve so that ๐’…๐’š ๐’…๐’• = ๐’…๐’“ ๐’…๐œฝ . Find the value of ๐’…๐’“ ๐’…๐’• at ๐œฝ= ๐… ๐Ÿ‘ and interpret answer in terms of motion of the particle. 4/24/ :25 PM ยง10.5C: Polar AP Practice

12 Example 3c The graphs of the polar curves of ๐’“=๐Ÿ and ๐’“=๐Ÿ‘+๐Ÿ ๐œ๐จ๐ฌ ๐œฝ are shown. The curves intersect when ๐œฝ= ๐Ÿ๐… ๐Ÿ‘ and ๐œฝ= ๐Ÿ’๐… ๐Ÿ‘ . (c) For the particle described in part (b), ๐’…๐’š ๐’…๐’• = ๐’…๐’“ ๐’…๐œฝ , find the value of ๐’…๐’š ๐’…๐’• at ๐œฝ= ๐… ๐Ÿ‘ and interpret answer in terms of motion of the particle. 4/24/ :25 PM ยง10.5C: Polar AP Practice

13 Example 3c The graphs of the polar curves of ๐’“=๐Ÿ and ๐’“=๐Ÿ‘+๐Ÿ ๐œ๐จ๐ฌ ๐œฝ are shown. The curves intersect when ๐œฝ= ๐Ÿ๐… ๐Ÿ‘ and ๐œฝ= ๐Ÿ’๐… ๐Ÿ‘ . (c) For the particle described in part (b), ๐’…๐’š ๐’…๐’• = ๐’…๐’“ ๐’…๐œฝ , find the value of ๐’…๐’š ๐’…๐’• at ๐œฝ= ๐… ๐Ÿ‘ and interpret answer in terms of motion of the particle. 4/24/ :25 PM ยง10.5C: Polar AP Practice

14 Example 3c The graphs of the polar curves of ๐’“=๐Ÿ and ๐’“=๐Ÿ‘+๐Ÿ ๐œ๐จ๐ฌ ๐œฝ are shown. The curves intersect when ๐œฝ= ๐Ÿ๐… ๐Ÿ‘ and ๐œฝ= ๐Ÿ’๐… ๐Ÿ‘ . (c) For the particle described in part (b), ๐’…๐’š ๐’…๐’• = ๐’…๐’“ ๐’…๐œฝ , find the value of ๐’…๐’š ๐’…๐’• at ๐œฝ= ๐… ๐Ÿ‘ and interpret answer in terms of motion of the particle. 4/24/ :25 PM ยง10.5C: Polar AP Practice

15 Example 4 A curve is drawn in the ๐’™๐’š-plane and is described by the equation in polar coordinates ๐’“=๐œฝ+๐ฌ๐ข๐ง ๐Ÿ๐œฝ for ๐ŸŽโ‰ค๐œฝโ‰ค๐…. Using the calculator: Find the area bounded by the curve and ๐’™-axis Find the angle ๐œฝ that corresponds to the point on the curve with ๐’™-coordinate ๐’™=โˆ’๐Ÿ. For ๐… ๐Ÿ‘ <๐œฝ< ๐Ÿ๐… ๐Ÿ‘ , ๐’…๐’“ ๐’…๐œฝ is negative. What does your answer tell you about ๐’“? What does it tell you about the curve? At what angle ๐œฝ is the interval ๐ŸŽโ‰ค๐œฝโ‰ค ๐… ๐Ÿ the curve farthest away from the origin. Justify. 4/24/ :25 PM ยง10.5C: Polar AP Practice

16 Example 4a A curve is drawn in the ๐’™๐’š-plane and is described by the equation in polar coordinates ๐’“=๐œฝ+๐ฌ๐ข๐ง ๐Ÿ๐œฝ for ๐ŸŽโ‰ค๐œฝโ‰ค๐…. Using the calculator: Find the area bounded by the curve and x-axis 4/24/ :25 PM ยง10.5C: Polar AP Practice

17 Example 4b A curve is drawn in the ๐’™๐’š-plane and is described by the equation in polar coordinates ๐’“=๐œฝ+๐ฌ๐ข๐ง ๐Ÿ๐œฝ for ๐ŸŽโ‰ค๐œฝโ‰ค๐…. Using the calculator: b) Find the angle ๐œฝ that corresponds to the point on the curve with ๐’™-coordinate ๐’™=โˆ’๐Ÿ. 4/24/ :25 PM ยง10.5C: Polar AP Practice

18 Example 4c A curve is drawn in the ๐’™๐’š-plane and is described by the equation in polar coordinates ๐’“=๐œฝ+๐ฌ๐ข๐ง ๐Ÿ๐œฝ for ๐ŸŽโ‰ค๐œฝโ‰ค๐…. For ๐… ๐Ÿ‘ <๐œฝ< ๐Ÿ๐… ๐Ÿ‘ , ๐’…๐’“ ๐’…๐œฝ is negative. What does your answer tell you about ๐’“? What does it tell you about the curve? ๐’…๐’“ ๐’…๐œฝ is how fast the radius is changing with respects to rotation. Since ๐’…๐’“ ๐’…๐œฝ is negative it is away from the pole/origin. 4/24/ :25 PM ยง10.5C: Polar AP Practice

19 Example 4d A curve is drawn in the ๐’™๐’š-plane and is described by the equation in polar coordinates ๐’“=๐œฝ+๐ฌ๐ข๐ง ๐Ÿ๐œฝ for ๐ŸŽโ‰ค๐œฝโ‰ค๐…. At what angle ๐œฝ is the interval ๐ŸŽโ‰ค๐œฝโ‰ค ๐… ๐Ÿ the curve farthest away from the origin. Justify. 4/24/ :25 PM ยง10.5C: Polar AP Practice


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