Download presentation
Presentation is loading. Please wait.
Published byἈλκαῖος Κουρμούλης Modified over 5 years ago
1
Solving a System of Linear and Quadratic Equations Algebraically
See the back of this flipbook for a review on how to solve a system of linear equations using SUBSTITUTION. SUBSTITUTION was used because it is the only method we can use to solve linear-quadratic systems algebraically. Because we are dealing with quadratic equations, it is natural to expect more than one answer. Consider the sketch of a line and a parabola. Example 1 a. What is the maximum number of intersection points that a line and a parabola could have? Illustrate with a picture. b. What is the minimum number of intersection points c. Is it possible for a line and a parabola to intersect in only one point? If so, illustrate with a picture.
2
3. Use a graphing calculator to solve the system below. Use the
3. Use a graphing calculator to solve the system below. Use the “Calculate Intersection” and “Table” features. Find a good window where you can see both equations and their intersection points clearly. Draw a picture of your screen and state the window you used. Xmin= Xmax= Xscl= Ymin= Ymax= Yscl=
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.