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Percent Concentration

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Presentation on theme: "Percent Concentration"— Presentation transcript:

1 Percent Concentration
Chapter 7 Solutions 7.4 Percent Concentration

2 Percent Concentration
The concentration of a solution is the amount of solute dissolved in a specific amount of solution. amount of solute amount of solution

3 Mass Percent Mass percent (%m/m) is the
concentration is the percent by mass of solute in a solution. mass percent = g of solute x 100 g of solute + g of solvent amount in g of solute in 100 g of solution. mass percent = g of solute x 100 100 g of solution

4 Mass of Solution Add water to give 50.00 g solution 8.00 g KCl
50.00 g KCl solution Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings

5 Calculating Mass Percent
The calculation of mass percent (%m/m) requires the grams of solute (g KCl) and grams of solution (g KCl solution). g of KCl = g g of solvent (water) = g g of KCl solution = g 8.00 g KCl (solute) x 100 = 16.0% (m/m) 50.00 g KCl solution

6 Learning Check 1) 15.0% (m/m) Na2CO3 2) 6.38% (m/m) Na2CO3
A solution is prepared by mixing 15.0 g Na2CO3 and 235 g of H2O. Calculate the mass percent (%m/m) of the solution. 1) 15.0% (m/m) Na2CO3 2) 6.38% (m/m) Na2CO3 3) 6.00% (m/m) Na2CO3

7 Solution 3) 6.00% (m/m) Na2CO3 STEP 1 mass solute = 15.0 g Na2CO3
mass solution = g g = 250. g STEP 2 Use g solute/ g solution ratio STEP 3 mass %(m/m) = g solute x g solution STEP 4 Set up problem mass %(m/m) = 15.0 g Na2CO3 x 100 = 6.00% Na2CO3 250. g solution

8 Volume Percent The volume percent (%v/v) is
percent volume (mL) of solute (liquid) to volume (mL) of solution. volume % (v/v) = mL of solute x mL of solution solute (mL) in 100 mL of solution. volume % (v/v) = mL of solute mL of solution

9 Mass/Volume Percent The mass/volume percent (%m/v) is
percent mass (g) of solute to volume (mL) of solution. mass/volume % (m/v) = g of solute x mL of solution solute (g) in 100 mL of solution. mass/volume % (m/v) = g of solute mL of solution

10 Percent Conversion Factors
Two conversion factors can be written for each type of % value. TABLE 7.7 5% (m/v) glucose There are 5 g of glucose g glucose and mL solution in 100 mL of solution mL solution g glucose

11 Learning Check Write two conversion factors for each solutions.
A % (m/m) NaOH B. 5.75% (v/v) ethanol C % (m/v) HCl

12 Solution A. 8.50 g NaOH and 100 g solution 100 g solution 8.50 g NaOH
B mL alcohol and mL solution 100 mL solution mL alcohol C g HCl and mL HCl 100 mL solution g HCl

13 Using Percent Concentration (m/m) as Conversion Factors
How many grams of NaCl are needed to prepare 225 g of a 10.0% (m/m) NaCl solution? STEP 1 Given: 225 g solution; 10.0% (m/m) NaCl Need: g of NaCl STEP 2 g solution g NaCl STEP 3 Write the 10.0% (m/m) as conversion factors. 10.0 g NaCl and g solution 100 g solution g NaCl STEP 4 Set up using the factor that cancels g solution. 225 g solution x g NaCl = 22.5 g NaCl g solution

14 Learning Check 75.0 g of 14.0% (m/m) NaOH solution? 1) 10.5 g NaOH
How many grams of NaOH are needed to prepare 75.0 g of 14.0% (m/m) NaOH solution? 1) 10.5 g NaOH 2) g NaOH 3) 536 g NaOH

15 Solution 1) 10.5 g NaOH 75.0 g solution x 14.0 g NaOH = 10.5 g NaOH
14.0% (m/m) factor

16 Learning Check 1) 2.56 mL 2) 12.9 mL 3) 39.1 mL
How many milliliters of a 5.75% (v/v) ethanol solution can be prepared from 2.25 mL ethanol? 1) mL 2) mL 3) mL

17 Solution 3) 39.1 mL 2.25 mL ethanol x 100 mL solution 5.75 mL ethanol
5.75% (v/v) inverted = mL solution

18 Using Percent Concentration(m/v) as Conversion Factors
How many mL of a 4.20% (m/v) will contain 3.15 g KCl? STEP 1 Given: g KCl(solute); 4.20% (m/v) KCl Need: mL of KCl solution STEP 2 Plan: g KCl mL KCl solution STEP 3 Write conversion factors. 4.20 g KCl and mL solution 100 mL solution g KCl STEP 4 Set up the problem 3.15 g KCl x 100 mL KCl solution = mL KCl g KCl

19 Learning Check How many grams of NaOH are needed to prepare 125
mL of a 8.80% (m/v) NaOH solution?

20 Solution How many grams of NaOH are needed to prepare 125
mL of a 8.80% (m/v) NaOH solution? 125 mL solution x g NaOH = g NaOH 100 mL solution


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