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Published byPřemysl Procházka Modified over 5 years ago
1 Section 6.3 – Polynomial Division
2 3x 3x x
3 –3
4 3 -1 3 3 -1 -1 -1 1 1 -1 1 1 -1 1 -1 -1 1 -3
5 1 4 14
6 2 -4
7 3 -2
8 1 -3
9 2 5 -3
Remainder and Factor Theorems
27 Feb 2013 Saturday Division 2 Section 5 Ladder Round 18.
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EXAMPLE 3 Use synthetic division Divide f (x)= 2x 3 + x 2 – 8x + 5 by x + 3 using synthetic division. – – 8 5 – 6 15 – 21 2 – 5 7 – 16 2x 3 + x 2.
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Section 2.3 Polynomial and Synthetic Division Long Division of polynomials Ex. (6x 3 -19x 2 +16x-4) divided by (x-2) Ex. (x 3 -1) divided by (x-1) Ex (2x.
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Section 5.3(d) Synthetic Substitution. Long division Synthetic Division can be used to find the value of a function. This process is called Synthetic.
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Warm Up no 0, 3 x = -3. Homework Questions Section 2.2 Synthetic Division; The Remainder and Factor Theorems Objective: To use synthetic division and.
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