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Simulation Status of X(1835) at BESIII

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Presentation on theme: "Simulation Status of X(1835) at BESIII"— Presentation transcript:

1 Simulation Status of X(1835) at BESIII
J/ Group

2 X(1835) X(1835),(958)+- (,(958)(548)+- ) J/X(1835)
K+K-  +-0 KSKL

3 X(1835) Charged Tracks Charge = +1,-1 ΣQch = 0 Vertex Cut: Vr  1.0 cm
Vz  5.0cm Good  Selection Eneu  40.0 MeV (charge   )  20o (charge   )  20o

4 J/X(1835)(K+K-) Final States: 2 K+K- 2(+-) NGen = 100K
N4c = (1.6%) N5c = (0.9%)

5 J/X(1835)(K+K-)(4c)

6 J/X(1835)(K+K-)(5c)

7 J/X(1835)(K+K-)  ’(958) X(1835)  INPUT FIT 2 M=1.019456
=4.26e-3 1.01950.0001 2.9e-30.1e-3 34/31 ’(958) M= =2.02e-4 0.95690.0002 3.5e-30.1e-3 56/22 X(1835) M=1.835 =0.06 1.8380.001 2.4e-20.1e-2 108/26 M= =1.0e-4 0.56170.0002 7.8e-30.2e-3 97/69

8 J/X(1835)(+-0) Final States: 4 3(+-) NGen= 50K
N4c = (1.7%) N6c = (0.4%)

9 J/X(1835)(+-0)(6c)
X(1835) 1.835 0.06 ’(958)

10 J/X(1835) Final States: 4 3(+-) NGen = 100K N4c = 3099 (3.1%)

11 J/X(1835)(+-0)(6c)
X(1835) 1.835 0.06 ’(958)

12 J/X(1835) Final States: 3 2(+-) NGen = 100K N4c = 3960 (4.0%)

13 J/X(1835)(5c) X(1835) 1.835 0.06 ’(958)

14 X(1835) Gen: the output file *.dat is too LARGE
evt.dat (px, py, pz, e) *.dat ( MCtruth, raw) 2.0G/file Limit in Linux run.cards : evt_range *_sim.txt : EvtMax Total Energy(Fig.)  invariant mass after 5c or 6c

15 J/X(1835)(K+K-)   auto-decay


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