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Quadratics Friday, 26 April 2019.

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1 Quadratics Friday, 26 April 2019

2 Solving Quadratics Example Solve each of the following quadratics
b) 𝑑 2 βˆ’6𝑑=40 c) 10 π‘₯ 2 =π‘₯+2 b) 𝑑 2 βˆ’6𝑑=40 c) 10 π‘₯ 2 =π‘₯+2 a) π‘₯ 2 βˆ’11π‘₯+24=0 𝑑 2 βˆ’6π‘‘βˆ’40=0 10 π‘₯ 2 βˆ’π‘₯βˆ’2=0 π‘₯βˆ’3 π‘₯βˆ’8 =0 π‘‘βˆ’10 𝑑+4 =0 5π‘₯+2 2π‘₯βˆ’1 =0 π‘₯=3 π‘₯=8 𝑑=10 𝑑=βˆ’4 π‘₯=βˆ’ 2 5 π‘₯= 1 2

3 Example Show that the area of the shape drawn below can be given as π‘₯ 2 +8π‘₯+15 b) Hence given that the area is equal to 48 cm2 find the possible value of x.

4 A B a) Area A =π‘₯ π‘₯+2 =π‘₯ 2 +2π‘₯ Area B =3 2π‘₯+5 =6π‘₯+15 Area = π‘₯ 2 +8π‘₯+15
π‘₯ 2 +8π‘₯+15=48 π‘₯ 2 +8π‘₯βˆ’33=0 π‘₯βˆ’3 π‘₯+11 =0 π‘₯=3 π‘₯=βˆ’11 ∴π‘₯=3

5 Algebraic Fractions π‘₯ 2 βˆ’3π‘₯ π‘₯ 2 βˆ’2π‘₯βˆ’3 π‘₯ 2 βˆ’3π‘₯ π‘₯ 2 βˆ’2π‘₯βˆ’3
Example Factorise π‘₯ 2 βˆ’3π‘₯ Factorise π‘₯ 2 βˆ’2π‘₯βˆ’3 Hence simplify the fraction π‘₯ 2 βˆ’3π‘₯ π‘₯ 2 βˆ’2π‘₯βˆ’3 a) π‘₯ 2 βˆ’3π‘₯ =π‘₯ π‘₯βˆ’3 b) π‘₯ 2 βˆ’2π‘₯βˆ’3 = π‘₯βˆ’3 π‘₯+1 π‘₯ 2 βˆ’3π‘₯ π‘₯ 2 βˆ’2π‘₯βˆ’3 = π‘₯ π‘₯βˆ’3 π‘₯βˆ’3 π‘₯+1 = π‘₯ π‘₯+1 c)

6 π‘₯ 2 +4π‘₯ 2 π‘₯ 2 βˆ’10π‘₯ = π‘₯ π‘₯+4 2π‘₯ π‘₯βˆ’5 = π‘₯+4 2 π‘₯βˆ’5 π‘₯ 2 +6π‘₯+5 π‘₯ 2 βˆ’π‘₯βˆ’2
Example Write each of the following fractions in their simplest form π‘₯ 2 +4π‘₯ 2 π‘₯ 2 βˆ’10π‘₯ = π‘₯ π‘₯+4 2π‘₯ π‘₯βˆ’5 = π‘₯+4 2 π‘₯βˆ’5 (i) π‘₯ 2 +6π‘₯+5 π‘₯ 2 βˆ’π‘₯βˆ’2 = π‘₯+1 π‘₯+5 π‘₯+1 π‘₯βˆ’2 = π‘₯+5 π‘₯βˆ’2 (ii)

7 In order to simplify an Algebraic fraction
Ensure that both numerator and denominator are factorised Cancel any factors that are common to both numerator and denominator Example Write the following fractions in its simplest form 4 π‘₯ 2 +8π‘₯ 8 π‘₯ 2 βˆ’24π‘₯ = 4π‘₯ π‘₯+2 8π‘₯ π‘₯βˆ’3 = π‘₯+2 2 π‘₯βˆ’3 2

8 1. Write each of the following fractions in their simplest form
Questions 1. Write each of the following fractions in their simplest form Answer = (i) (ii) Answer = (iii) Answer =

9 (iv) Answer = (v) Answer = (vi) Answer =

10 2. solve each of the following equations
b) 3 π‘₯ 2 +4π‘₯+1=0 c) 4 π‘₯ 2 βˆ’4π‘₯βˆ’15=0 d) 10 π‘₯ 2 βˆ’π‘₯βˆ’2=0 e) 4 π‘₯ 2 =6βˆ’5π‘₯ Answer Answer Answer Answer Answer

11 3. The base of a triangle is 7 cm longer than its height
3. The base of a triangle is 7 cm longer than its height. The area of the triangle is 30 cm2. (a) Taking the height to be β„Ž cm, show that β„Ž2+ 7β„Ž βˆ’ 60 = 0 (b) Solve this equation to find the height of the triangle. Answer cm


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