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Chapter 25 Capacitance-II
In the last lecture: we calculated the capacitance C of a system of two isolated conductors. We also calculated the capacitance for some simple geometries. In this chapter we will cover the following topics: -Methods of connecting capacitors (in series , in parallel) Equivalent capacitance Energy stored in a capacitor Behavior of an insulator (a.k.a. dielectric) when placed in the electric field created in the space between the plates of a capacitor Gauss’ law in the presence of dielectrics. (25 - 1)
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HITT An electron moves from point i to point f, in the direction of a uniform electric field. During this displacement: i j A. the work done by the field is positive and the potential energy of the electron-field system increases B. the work done by the field is negative and the potential energy of the electron-field system increases C. the work done by the field is positive and the potential energy of the electron-field system decreases D. the work done by the field is negative and the potential energy of the electron-field system decreases E. the work done by the field is positive and the potential energy of the electron-field system does not change b
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(25 - 9)
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- + dq' q' -q' V' q' q V' V Charge Voltage O A B ( )
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- + q -q d A ( )
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q -q q' -q' V V' ( )
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q -q q' -q' V V' ( )
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q conductor dielectric ( )
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S ( )
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HITT A parallel-plate capacitor has a plate area of 0.2m2 and a plate separation of 0.1 mm. To obtain an electric field of 2.0 x 106 V/m between the plates, the magnitude of the charge on each plate should be: A. 8.9 x 10-7 C B. 1.8 x 10-6 C C. 3.5 x 10-6 C D. 7.1 x 10-6 C E. 1.4 x 10-5 C c
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