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Published byΠΠ°Π½ΠΈΠΈΠ» ΠΠ°ΡΠ°Π±Π°Π½ΠΎΠ² Modified over 5 years ago
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Domain, Range, Vertical Asymptotes and Horizontal Asymptotes
Rational Functions Domain, Range, Vertical Asymptotes and Horizontal Asymptotes
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What is a rational function?
Definition: A function of the form π(π₯) π(π₯) , where π(π₯) and π(π₯) are polynomials and π(π₯) is not the zero polynomial. π(π₯) π(π₯) ;π€βπππ π(π₯)β 0 What is the most common form of the equation? π π₯ = 1 π₯
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What does it look like? Domain:(ββ,0)βͺ(0,β) Range:(ββ,0)βͺ(0,β) X Y -3
β 1 3 -2 β 1 2 -1 ----- 1 2 1 2 3 1 3 Domain:(ββ,0)βͺ(0,β) Range:(ββ,0)βͺ(0,β)
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Asymptotes Definition:
Horizontal: The line π¦=π is a horizontal asymptote of the graph of a function f if lim π₯βββ π π₯ =π or lim π₯ββ π π₯ =π Vertical: The line π₯=π is a vertical asymptote of the graph of the function f if lim π₯β π + π π₯ =Β±β or lim π₯β π β π π₯ =Β±β
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What do Asymptotes look like?
Horizontal: π=π Vertical: π=π
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Finding Asymptotes Vertical Horizontal
lim π₯β π + π π₯ =Β±β or lim π₯β π β π π₯ =Β±β Where do they come from? Vertical asymptotes go through what axis? The X-Axis Thus, we are looking for discontinuities or values that x canβt be. In rational equations: π π₯ = 1 π₯ ;π₯β 0, as π₯ is in the denominator. Thus, we are going to set the values of the denominator >0 and solve for π₯. The asymptote is x=0. lim π₯βββ π π₯ =π or lim π₯ββ π π₯ =π Where do they come from? Horizontal asymptotes go through what axis? The Y-Axis Like radical equations, our horizontal asymptote changes when a value is being added or subtracted to the outside of the fraction. In rational equations: π π₯ = 1 π₯ β2 The asymptote that was π¦=0 is now π¦=β2.
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Horizontal Asymptotes
π π₯ = π π₯ π π π₯ π Cases: If π<π then π¦=0 If π=π, then π¦= π π If π>π then there is no H.A.
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Where are the asymptotes for the graph π π₯ = 1 π₯ ?
Horizontal: π=π Vertical: π=π
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Domain and Range: ββ,__ βͺ(__ ,β)
Domain: x-values Range: y-values Restrictions: Since the denominator can never equal zero. We must look at all values of x that would cause that to happen. Example: π¦= 1 π₯β3 ;π₯β3=0βπ₯β 3 Domain: ββ,3 βͺ(3,β) The missing value occurs at horizontal asymptote of the graph. The original asymptote is at π¦=0. Thus, we are looking at any vertical shifts that occur in the graph. Example: π¦= 1 π₯ β2 Range: ββ,β2 βͺ(β2,β)
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Graphs π¦= 1 π₯β3 π¦= 1 π₯ β2 Asymptotes: π₯=3 πππ π¦=0 Asymptotes:
π₯=0 πππ π¦=β2
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Examples π¦= π₯β5 π₯β3 π¦= π₯ 2 β9 π₯ 2 β4 Vertical Asymptote:
π¦= π₯ 2 β9 π₯ 2 β4 Vertical Asymptote: π₯β3=0βπ₯β 3 π₯=3 is the asymptote. Horizontal Asymptote: The degree of x in the numerator is the same as the degree of x in the denominator, so: 1π₯ 1π₯ β1 Domain: (ββ,3)βͺ(3,β) Range: (ββ,1)βͺ(1,β) Vertical Asymptote: π₯ 2 β4=0β π₯ 2 =4βπ₯=Β±2 π₯=2 πππ π₯=β2 are the asymptotes. Horizontal Asymptote: The degree of x in the numerator is the same as the degree of x in the denominator, so: 1 π₯ 2 1 π₯ 2 β1 Domain: (ββ,β2)βͺ β2, 2 βͺ(2,β) Range: (ββ,1)βͺ(1,β)
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Example #1 Graph π¦= 2π₯+5 π₯β1 Vertical Asymptote:
π₯β1=0βπ₯β 1 π₯=1 is the asymptote. Horizontal Asymptote: π=π so y= π π π¦= 2 1 β2 so π¦=2 is the asymptote. Domain: (ββ,1)βͺ(1,β) Range: (ββ,2)βͺ(2,β)
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Example #2 Graph π¦= 3π₯β1 π₯ 2 +4π₯β21 Vertical Asymptote:
π¦= 3π₯β1 π₯ 2 +4π₯β21 Graph Vertical Asymptote: π₯ 2 +4π₯β21β π₯+7 π₯β3 βπ₯β β7 and π₯β 3 So, π₯=β7 and π₯=3 are the asymptotes. Horizontal Asymptote: π<π The degree in the numerator is less than the degree in the denominator so π¦=0. Domain: (ββ,β7)βͺ(β7, 3)βͺ(3,β) Range: (ββ,0)βͺ(0,β)
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Example #3 Graph π¦= π₯ 3 β8 π₯ 2 +5π₯+6 Vertical Asymptote:
π¦= π₯ 3 β8 π₯ 2 +5π₯+6 Vertical Asymptote: π₯ 2 +5π₯β6β π₯+3 π₯+2 βπ₯β β3 and π₯β β2 So, π₯=β3 and π₯=β2 are the asymptotes. Horizontal Asymptote: π>π so there is no H.A. Domain: (ββ,β3)βͺ β3, β2 βͺ(β2,β) Range: (ββ,β)
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Hole Definition: HolesΒ in the graph of a rational function are generally produced byΒ factors that are common to both the numerator and the denominator!Β Example: π π₯ = π₯ 2 (π₯β2) π₯β2 π π₯ = π₯ 2 (π₯β2) π₯β2 βπ π₯ = π₯ 2 π₯β2=0βπ₯=2 Thus, there is a hole at π₯=2.
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Example #4 π¦= π₯+2 π₯ 2 βπ₯β6 Continuedβ¦ Domain: Range:
π¦= π₯+2 π₯ 2 βπ₯β6 Continuedβ¦ Vertical Asymptote: π₯ 2 βπ₯β6β π₯β3 π₯+2 However, π₯+2 is the numerator so it cancels and a hole in the graph occurs. S0, π₯=3 is the only V.A. Horizontal Asymptote: π<π so π¦=0. Also, because there is a hole we must find the y-coordinates of the hole. π¦=0 is the asymptote. Domain: (ββ,β3)βͺ(β3,β) Range: (ββ,0)βͺ(0,β)
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Graph π=π π=π π¦= π₯+2 π₯ 2 βπ₯β6
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