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Acids Lesson 9 Weak Acids pH Calculations.

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Presentation on theme: "Acids Lesson 9 Weak Acids pH Calculations."— Presentation transcript:

1 Acids Lesson 9 Weak Acids pH Calculations

2 1. Calculate the pH of 0.45 M HCN.
You need an ICE chart for weak acids or bases! HCN ⇄ H+ + CN- I 0.45 M 0 0 C x x x E x x x Ka = [H+][CN-] = 4.9 x [HCN] Ka = x2 = 4.9 x x

3 The Ka is small, so x is small
We will find that x = = 0.45 This means we can make the approximation that x = 0.45 We can do this anytime the Ka has an exponent of 10-4 or less Ka = x2 = 4.9 x x 0 small ka

4 x2 = 4.9 x 0.45 x = [H+] = M pH = -Log[ ] pH = 4.83 2 sig figs due to molarity and Ka

5 2. Calculate the pH of 0.60 M H3BO3
H3BO3 ⇄ H+ + H2BO3- I 0.60 M 0 0 C x x x E x x x 0 small ka x2 = 7.3 x 0.60

6 x2 = 7.3 x 0.60 x = [H+] = x M pH = -Log[2.09 x 10-5] pH = 4.68 2 sig figs due to molarity and Ka

7 3. Calculate the pH of a 0.20 M diprotic acid with a
Ka = x 10-7 H2X ⇄ H+ + HX- I 0.20 M 0 0 C x x x E x x x 0 small ka x2 = 4.7 x 10-7 0.20

8 x = [H+] = x M pH = -Log[ x 10-4] pH = 3.51 2 sig figs due to molarity and Ka

9 4. Calculate the pH of a saturated solution of Mg(OH)2.
This is a solubility equilibrium- no ICE Mg(OH)2(s) ⇄ Mg2+ + 2OH- s s 2s Ksp = [Mg2+]][OH-]2 = x [s][2s]2 = x 4s3 = x s = x M

10 2s = [OH-] = x M pOH = 3.65 pH = 10.35


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