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Methods in calculus
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FM Methods in Calculus: Improper integrals
KUS objectives BAT evaluate improper integrals; the mean of a function; Integrate using trig substitution; integrate using partial fractions Starter: find 5๐ฅ 3+ ๐ฅ 2 ๐๐ฅ =5 3+ ๐ฅ 2 +๐ถ ๐ฅ 2 ๐ ๐ฅ ๐๐ฅ = ๐ฅ 2 โ2๐ฅ+2 ๐ ๐ฅ +๐ถ sin ๐ฅ cos ๐ฅ 1+3 ๐ ๐๐ 2 ๐ฅ ๐๐ฅ =๐๐ 1+3 ๐ ๐๐ 2 ๐ฅ +๐ถ
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The integral ๐ ๐ ๐(๐ฅ) ๐๐ฅ is improper if
Notes ๐ด๐๐๐= ๐ ๐ ๐(๐ฅ) ๐๐ฅ A definite integral represents the area enclosed by a continuous function ๐ฆ=๐(๐ฅ), the x-axis and line ๐ฅ=๐ and ๐ฅ=๐ ๐ ๐ฆ ๐ฅ ๐ฆ= 1 ๐ฅ 2 ๐ (1) ๐ด๐๐๐= ๐ โ 1 ๐ฅ 2 ๐๐ฅ An Improper integral represents the area where one of the limits is infinite or where the function is not defined at some point The integral ๐ ๐ ๐(๐ฅ) ๐๐ฅ is improper if one or both of the limits is infinite f(x) is undefined at ๐ฅ=๐ or ๐ฅ=๐ or at a point in the interval [a, b] ๐ ๐ฆ ๐ฅ ๐ฆ= 1 ๐ฅ 3 (2) ๐ด๐๐๐= ๐ฅ ๐๐ฅ If the improper integral exists it is said to be convergent. If it does not exist it is said to be divergent
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WB A1- limits of inifinity Evaluate each improper integral
๐) 1 โ 1 ๐ฅ 2 ๐๐ฅ ๐) 1 โ 1 ๐ฅ ๐๐ฅ Use limit notation to rewrite the integral as ๐๐๐ ๐กโโ 1 ๐ก 1 ๐ฅ 2 ๐๐ฅ = ๐๐๐ ๐กโโ โ 1 ๐ฅ ๐ก 1 = ๐๐๐ ๐กโโ โ 1 ๐ก +1 ๐๐ ๐กโโ , 1 ๐ก โ0 =๐ b) ๐๐๐ ๐กโโ 1 ๐ก 1 ๐ฅ ๐๐ฅ = ๐๐๐ ๐กโโ ln ๐ฅ ๐ก 1 = ๐๐๐ ๐กโโ ln ๐ก โ ln 1 ๐๐ ๐กโโ , ln ๐ก โโ ๐
๐๐๐ ๐๐๐ ๐๐๐๐๐๐๐๐
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WB A2 - undefined limits Evaluate each improper integral
๐) ๐ฅ 2 ๐๐ฅ ๐) 0 2 ๐ฅ 4โ ๐ฅ 2 ๐๐ฅ Use limit notation to rewrite the integral as ๐๐๐ ๐กโ0 ๐ก ๐ฅ 2 ๐๐ฅ = ๐๐๐ ๐กโ0 โ 1 ๐ฅ 1 ๐ก = ๐๐๐ ๐กโ0 โ1+ 1 ๐ก ๐๐ ๐กโ0 , 1 ๐ก โโ โ1+ 1 ๐ก โโ as ๐กโ0 ๐
๐๐๐ ๐๐๐ ๐๐๐๐๐๐๐๐ b) ๐๐๐ ๐กโ2 0 ๐ก ๐ฅ 4โ ๐ฅ 2 ๐๐ฅ = ๐๐๐ ๐กโ2 โ 4โ ๐ฅ 2 ๐ก 0 The function is undefined for ๐ฅ=2 = ๐๐๐ ๐กโ2 โ 4โ ๐ก 2 +โ 4โ 0 2 ๐๐ ๐กโ2 , 4โ ๐ก 2 โ0 = (0) = 2
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NOW DO EX 3A WB A3 โ both limits are infinity a) Find ๐ฅ ๐ โ ๐ฅ 2 ๐๐ฅ
b) Hence show that converges and find its value โโ โ ๐ฅ ๐ โ ๐ฅ 2 ๐๐ฅ โโ โ ๐ฅ ๐ โ ๐ฅ 2 ๐๐ฅ =โ 1 2 ๐ โ ๐ฅ 2 +C b) โโ โ ๐ฅ ๐ โ ๐ฅ 2 ๐๐ฅ = โโ 0 ๐ฅ ๐ โ ๐ฅ 2 ๐๐ฅ + 0 โ ๐ฅ ๐ โ ๐ฅ 2 ๐๐ฅ Split into two improper integrals = ๐๐๐ ๐กโโ โ 1 2 ๐ โ ๐ฅ โ๐ก ๐๐๐ ๐กโโ โ 1 2 ๐ โ ๐ฅ 2 ๐ก 0 = ๐๐๐ ๐กโโ โ 1 2 โโ 1 2 ๐ โ ๐ก ๐๐๐ ๐กโโ โ 1 2 ๐ โ ๐ก 2 โโ 1 2 ๐๐ ๐กโโ , ๐ โ ๐ก 2 โ both integrals converge = โ = 0 The areas cancel out NOW DO EX 3A
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One thing to improve is โ
KUS objectives BAT evaluate improper integrals; the mean of a function; Integrate using trig substitution; integrate using partial fractions self-assess One thing learned is โ One thing to improve is โ
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