1. Volume of Cones Find the volume of the figure. Use 3.14 for p.
Course 3
Volume of Cones
Find the volume of the figure. Use 3.14 for p.
B = (32) = 9 in2 1 3
V = • 9 • 10
V = Bh 1 3
V = 30  94.2 in3
Use 3.14 for .

2. Insert Lesson Title Here
Course 3
Volume of Cones
Insert Lesson Title Here
A cone has a radius of 2 m and a height of 5 m. Explain whether doubling the height would have the same effect on the volume of the cone as doubling the radius.
Double the Radius
Double the Height
Original Dimensions 1 3
V = pr2h
= p(22)5
 m3
V = pr2 (2h)
= p(22)(2•5)
= p(2 • 2)2(5)
V = p (2r)2h
 m3
 m3
When the height of a cone is doubled, the volume is doubled. When the radius is doubled, the volume is 4 times the original volume.

3. Volume of Cones Example 3
Course 3
Volume of Cones
Example 3
Find the volume of the figure. Use 3.14 for p.
B = (32) = 9 m2
7 m 1 3
V = • 9 • 7
V = Bh 1 3
3 m
V = 21  65.9 m3
Use 3.14 for .

4. Example 4: Exploring the Effects of Changing Dimensions
Course 3
Volume of Cones
Example 4: Exploring the Effects of Changing Dimensions
A cone has a radius of 3 ft. and a height of 4 ft. Explain whether tripling the height would have the same effect on the volume of the cone as tripling the radius.
When the height of the cone is tripled, the volume is tripled. When the radius is tripled, the volume becomes 9 times the original volume.

5. Example 5: Using a Calculator to Find Volume
Course 3
Volume of Cones
Example 5: Using a Calculator to Find Volume
Use a calculator to find the volume of a cone to the nearest cubic centimeter if the radius of the base is 15 cm and the height is 64 cm.
Use the pi button on your calculator to find the area of the base. p
2ND ^  15
B = pr2 X2
ENTER
Next, with the area of the base still displayed, find the volume of the cone.
V = Bh 1 3  64  ( 1 ÷ 3 )
ENTER
The volume of the cone is approximately 15,080 cm3.