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Topic 5 Riding the Hills (2.4) 5/2/2019 Riding the Hills.

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Presentation on theme: "Topic 5 Riding the Hills (2.4) 5/2/2019 Riding the Hills."— Presentation transcript:

1 Topic 5 Riding the Hills (2.4) 5/2/2019 Riding the Hills

2 The Telegraph Hill Bike Race
5/2/2019 Riding the Hills

3 Example 2.7 va vd vc vb 1Ω 2Ω 3Ω 4Ω 5Ω 6Ω 7Ω v1 v2 v3 v4 v5 v6 v7 + -
Write KVL around the four loops shown c b e d How many loops are there? 2-way combinations 3-way combinations a-b a-c b-c b-e c-e a-b-c a-b-e a-c-e b-c-e 5/2/2019 Riding the Hills

4 KVL around Loop a 1Ω 2Ω - + v1 v2 a vb 3Ω 4Ω v4 v3 va vc 5Ω v5 6Ω v6
vd vc vb v1 v2 v3 v4 v5 v6 v7 + - a 5/2/2019 Riding the Hills

5 If you don’t like uphill being negative…. a
va vd vc vb v1 v2 v3 v4 v5 v6 v7 + - If you don’t like uphill being negative…. a ….reverse all the signs! Just make sure you’re consistent! 5/2/2019 Riding the Hills

6 Loop b va vd vc vb 1Ω 2Ω 3Ω 4Ω 5Ω 6Ω 7Ω v1 v2 v3 v4 v5 v6 v7 + - b
5/2/2019 Riding the Hills

7 Loop c va vd vc vb 1Ω 2Ω 3Ω 4Ω 5Ω 6Ω 7Ω v1 v2 v3 v4 v5 v6 v7 + - c
5/2/2019 Riding the Hills

8 Loop d (outer loop) 1Ω 2Ω - + v1 v2 vb 3Ω 4Ω v4 v3 va vc 5Ω v5 6Ω v6
vd vc vb v1 v2 v3 v4 v5 v6 v7 + - Loop d (outer loop) d 5/2/2019 Riding the Hills

9 By KCL, i5 is the current flowing through the entire circuit
Assesment 2.5 24 v2 v5 v1 + - i5 For the circuit shown, calculate (a) i5; (b) v1; (c) v2; (d) v5; and (e) the power delivered by the 24v source i5 i5 (a) By KCL, i5 is the current flowing through the entire circuit By KVL : Applying Ohm’s Law at each Resistor: So & 5/2/2019 Riding the Hills

10 i5 Assesment 2.5 24 v2 v5 v1 + - i5 For the circuit shown, calculate (a) i5; (b) v1; (c) v2; (d) v5; and (e) the power delivered by the 24v source i5 i5 (b) Because i5 is defined to be flowing into the – terminal of v1 Again, from the point of view of i5 Note that if we follow around the circuit in the direction of the current v2 & v5 are downhill v1 has been defined as uphill, but v1 is negative so it’s actually downhill as well 5/2/2019 Riding the Hills

11 i5 Assesment 2.5 24 v2 v5 v1 + - i5 For the circuit shown, calculate (a) i5; (b) v1; (c) v2; (d) v5; and (e) the power delivered by the 24v source i5 i5 (c) Note (d) (e) delivered absorbed 5/2/2019 Riding the Hills

12 Problem 2.8 15A 5A 50v 10v 40v If the interconnections are valid find the total power developed. If not, explain why. ix vy + - 1 Writing KCL at node 1: The only two unknowns are ix and vy no conflict Writing KVL around loop a: no conflict So 5/2/2019 Riding the Hills

13 Problem 2.8 Source Other power 15A 50v -750w delivered 20A 1000w
If the interconnections are valid find the total power developed. If not, explain why. 20A -20v + - 1 Source Other power 15A 50v -750w delivered 20A 1000w absorbed 10v 5A 50w 40v -200w -20v -100w delivered = absorbed 5/2/2019 Riding the Hills

14 (a) Construct a circuit model for the device
ii Example 2.9 vi ii 30 15 3 6 + The terminal voltage and current were measured for the device shown and tabulated in the table device vi - (a) Construct a circuit model for the device 30 15 3 6 ii vi A v When ii = 0, vi = 30 Straight line equn. 30v + - ii vi KVL So 5/2/2019 Riding the Hills

15 b) Predict the power this device will deliver to a 10 ohm resistor
ii Example 2.9 vi ii 30 15 3 6 + The terminal voltage and current were measured for the device shown and tabulated in the table device vi - b) Predict the power this device will deliver to a 10 ohm resistor KVL around loop 30v + - ii 10Ω vi vy 5/2/2019 Riding the Hills

16 24 v2 v5 v1 + - i5 5/2/2019 Riding the Hills


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