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Newton’s Second Law of motion (牛頓運動第二定律)
Ch.8 Newton’s Second Law of motion (牛頓運動第二定律)
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100 N 200 N 100 N N = 300 N Left 5
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300 N 400 N 300 N N = 700 N North 7
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100 N 250 N -100 N N = 150 N Right 9
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500 N 300 N 500 N N = 200 N South 11
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200 N 300 N 500 N 500 N N – 200 N = 0 no direction
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Newton’s 2nd Law of Motion
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F = 100 N
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F = 100 N a = F m = 100 20 = 5 m s-2
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F = 100 – 40 = 60 N
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F = 100 – 40 = 60 N a = F m = 60 20 = 3 m s-2
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Thrust = Drag Lift = Weight It is because the aeroplane is moving at constant velocity means acceleration = 0 , i.e. the resultant force = 0.
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Thrust > Drag It is because a resultant force in forward direction is acting on the aeroplane.
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R F = 0 R = W = 650 N W
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F = ma = (65) (2) = 130 N R’ – W = ma R’ = W + ma = 650 + 130 = 780 N
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F = ma = (65) (-2) = -130 N R” – W = ma R” = W + ma = 650 + (-130)
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F = 0 It is because the trolley is moving with constant velocity means acceleration = 0. (friction = 100 N)
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F = 200 N
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F = 200 N a = F m = 200 25 = 9 m s-2
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F = 200 – 100 – 100 (friction = 100 N) = 0 a = F m = 0 200 N
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