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Algebra II Chapter 1 Review.

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Presentation on theme: "Algebra II Chapter 1 Review."— Presentation transcript:

1 Algebra II Chapter 1 Review

2 Simplify: 21 - [(24 + 3) - 2(3)2]

3 Simplify: 21 - [(24 + 3) - 2(3)2] 21 - [27-18] 21-9 = 12

4 Evaluate: 4x2 - 2xy for x= -2 and y= 5

5 4x2 - 2xy 4(-2)2-2(-2)(5) 4(4)+4(5) 16+20 = 36
Evaluate: 4x2 - 2xy 4(-2)2-2(-2)(5) 4(4)+4(5) 16+20 = 36

6 State each property: a. (2 + (-3)) + 7 = 2 + ((-3) + 7 ) b. 5(2x) = (2x)5 c. 4(2 + 9) = 4(2) + 4(9)

7 Sets of Numbers: Put a check in the box if the number belongs to that set.

8 Simplify: 1/2 (8x - 12) + 1/5 (10x - 15)

9 Simplify: 1/2 (8x - 12) + 1/5 (10x - 15) 4x-6+2x-3 6x-9

10 Solve: -5(m - 5) = 3(10 - 2m) + 10m

11 -5(m - 5) = 3(10 - 2m) + 10m -5m+25 = 30-6m+10m -5m+25 = 30+4m -9m = 5
Solve: -5(m - 5) = 3(10 - 2m) + 10m -5m+25 = 30-6m+10m -5m+25 = 30+4m -9m = 5 m = -5/9

12 Solve: 3(t + 7) > t

13 3(t + 7) > 31 - 2t 3t+21>31-2t 5t>10 t>2
Solve: 3(t + 7) > t 3t+21>31-2t 5t>10 t>2

14 Solve and Graph: 5 < 2x + 7 < 27

15 5 < 2x + 7 < 27 -2<2x<20 -1<x<10
Solve and Graph: 5 < 2x + 7 < 27 -2<2x<20 -1<x<10

16 Solve: 2|x - 3| - 2 = 8

17 2|x - 3| - 2 = 8 2|x-3|=10 x-3=5 or x-3=-5 x=8 or x=-2
Solve: 2|x - 3| - 2 = 8 2|x-3|=10 x-3=5 or x-3=-5 x=8 or x=-2

18 Solve: |4x + 9| > -2

19 |4x + 9| > -2 4x+9>-2 or 4x+9<2 4x>-11 or 4x<-7
Solve: |4x + 9| > -2 4x+9>-2 or 4x+9<2 4x>-11 or 4x<-7 x>-11/4 or x<-7/4 all real numbers


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