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Published byKristopher Bond Modified over 5 years ago
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Design of a Pipe 7 101 Runoff 102 1 Link 101 8 Inflow 102 102 9 Outflow 101 2 Link 102 3 10 103 11 Outflow 102 4 5 6 In a tree network, each node can have only one outflow link. Therefore we use the convention that link numbers are the same as the upstream node number.
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Get the Maximum Inflow If no inflow hydrograph exists the user can specify a peak flow for the design Use Hydrograph|Add Runoff to update Inflow hydrograph
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Uniform Flow in Pipes Solve for y0 using
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Critical Depth in Pipes
Solution for Ycr is based on the minimum energy criterion
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A Trial Pipe Design Table of feasible designs for given Q and ‘n’
Double click on a row to test trial design Click [Design] to get results of part-full flow analysis
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Surcharged Pipes Due to closed top boundary resistance increases
as depth y approaches diameter D. At y = D Q = Qfull Q/Qfull When y = D Q = Qfull. y/D
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Surcharged Pipes Q > Qfull Q = Qfull Q < Qfull
Energy line Q > Qfull Water surface Q = Qfull Q < Qfull MIDUSS 98 assumes uniform flow for part-full pipes
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Exercise 4 Design a pipe to carry 2 c.m/s when running 75% full with a gradient of 0.4% and n = 0.013 Check for surcharged hydraulic grade line if discharge increases to 3 c.m/s
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