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Sudocodes Fast measurement and reconstruction of sparse signals
Shriram Sarvotham Dror Baron Richard Baraniuk ECE Department Rice University dsp.rice.edu/cs Came out of my personal experience with 301 – fourier analysis and linear systems
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Motivation: coding of sparse data
Streaming in CDNs, distributed storage systems Delivery of content that has sparse representation E.g. thresholded DCT/wavelet coefficients in JPEG/JPEG2000 Distributed coding of sparse data
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Sparse signal Acquisition
Consider that contains only non-zero coefficients Are there efficient ways to measure and recover ? Traditional DSP approach: Acquisition: obtain measurements Sparsity is exploited only in the processing stage New Compressed Sensing (CS) approach: Acquisition: obtain just measurements Sparsity is exploited during signal acquisition [Candes et al; Donoho]
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Compressive Sampling Signal is -sparse in basis/dictionary
WLOG assume sparsity in space domain Measure signal via few linear projections sparse signal measurements nonzero entries
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Compressive Sampling Signal is -sparse in basis/dictionary
WLOG assume sparsity in space domain Measure signal via few linear projections Random Gaussian measurements will work! sparse signal measurements nonzero entries
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CS Miracle: L1 reconstruction
Find the solution with smallest L1 norm [Candes et al; Donoho] If then perfect reconstruction w/ high probability sparse signal measurements nonzero entries
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CS Miracle: L1 reconstruction
Performance Efficient encoding, and Polynomial complexity reconstruction sparse signal measurements nonzero entries
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CS Miracle: L1 reconstruction
But… is still impractical for many applications Reconstruction times: N=1,000 t=10 seconds N=10,000 t=3 hours N=100,000 t=~months sparse signal measurements nonzero entries
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Why is reconstruction expensive?
sparse signal measurements nonzero entries
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Why is reconstruction expensive?
Culprit: dense, unstructured sparse signal measurements nonzero entries
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Fast CS reconstruction
Sudocode matrix (sparse) Only 0/1 in Each row of contains randomly placed 1’s sparse signal measurements nonzero entries
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Fast CS reconstruction
Sudocode performance Efficient encoding Sublinear complexity reconstruction Encouraging numerical results N=100,000 K=1,000 t=5.47 seconds M=5,132 sparse signal measurements nonzero entries
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Signal model Signal is strictly sparse sparse signal measurements
nonzero entries
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Signal model Signal is strictly sparse
Every nonzero ~ continuous distribution each nonzero coefficients is unique almost surely sparse signal measurements nonzero entries
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Sudocode reconstruction
Process each in succession Each can recover some ‘’s sparse signal measurements nonzero entries
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Sudocode reconstruction
Like sudoku puzzles! sparse signal measurements nonzero entries
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Case 1: Zero measurement
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Case 1: Zero measurement
Resolves all coefficients in the support Can resolve up to coefficients
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Case 1: Zero measurement
Resolves all coefficients in the support Can resolve up to coefficients Reduces size of problem
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Case 2: #(support set)=1
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Case 2: #(support set)=1 Trivially resolves
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Case 2: #(support set)=1 Trivially resolves
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Case 3: Matching measurements
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Case 3: Matching measurements
Matches originate from same support Disjoint support coefficients = 0 Common support contain nonzeros Common support
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Case 3: Matching measurements
Matches originate from same support Disjoint support coefficients = 0 Common support contain nonzeros
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Trigger of revelations
Recovery of can trigger more revelations
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Trigger of revelations
Recovery of can trigger more revelations An avalanche of coefficient revelations
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Trigger of revelations
Recovery of can trigger more revelations An avalanche of coefficient revelations
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Auxiliary data structures
Bottleneck: search for matches With Binary Search Tree, matches ~ Re-explain measurements: more data structures Search for matches
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Design of Sudo measurement matrix
Choice of L Set L based on For large N,
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Number of measurements
Theorem: With , decoder requires to exactly reconstruct coefficients Proof sketch:
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Choice of L K=0.02N For a given choice of N and K
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Choice of L Numerical evidence also suggests L = O(N/K)
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Related work [Cormode, Muthukrishnan]
CS scheme based on group testing Complexity [Gilbert et. al.] Chaining Pursuit CS scheme based on group testing and iterating Works best for super-sparse signals
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Performance comparison
Chaining Pursuit Sudocodes N=10,000 K=10 M=5,915 t=0.16 sec M=461 t=0.14 sec K=100 M=90,013 t=2.43 sec M=803 t=0.37 sec N=100,000 M=17,398 t=1.13 sec M=931 t=1.09 sec K=1000 M>106 t>30 sec M=5,132 t=5.47 sec
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Sudocode applications
Erasure codes in p2p and distributed file storage Stream compressed digital content Thresholded DCT/wavelet coefficients for sudocoding Partial reconstruction of signals (e.g. detection)
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Ongoing work Statistical dependencies between non-zero coefficients
Adaptive linear projections Noisy measurements
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Erasure coding
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Conclusions Sudocodes for CS Key idea: use sparse
highly efficient low complexity Key idea: use sparse Applications to erasure codes, P2P networks
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Number of measurements
Theorem: With , phase 1 requires to exactly reconstruct coefficients Proof sketch:
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Two phase decoding is not measured Phase 1: decode coefficients
Phase 2: decode remaining coefficients Why? When most coefficients are decoded, Phase 2 saves a factor of measurements
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Phase 2 measurements and decoding
is non-sparse of dimension
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Phase 2 measurements and decoding
is non-sparse of dimension Resolve remaining coefficients by inverting the sub-matrix of
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Phase 2 measurements and decoding
is non-sparse of dimension Resolve remaining coefficients by inverting the sub-matrix of Phase 2 complexity = Key: choose Phase 2 complexity is
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Compressive Sampling Signal is -sparse in basis/dictionary
WLOG assume sparsity in space domain Measure signal via few linear projections Random sparse measurements will work! sparse signal measurements nonzero entries
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