Presentation is loading. Please wait.

Presentation is loading. Please wait.

Problem of the Day! Q12 Job 26 Monday Mar 27

Similar presentations


Presentation on theme: "Problem of the Day! Q12 Job 26 Monday Mar 27"— Presentation transcript:

1 Problem of the Day! Q12 Job 26 Monday Mar 27
Draw the graph of y = x2 – 4x - 1 Graph Paper will be provided! Note: Friday Quiz Question!

2 Objective: Students can graph Quadratics
Agenda: -Problem of the Day -Cumulative Rev Quadratics Extra Help?? Library 3-5 Daily Take Home Test: Job 26 Test: Unit 6 Friday 31 Mar

3 Parabola

4 At what time is the ball at its greatest height?
Graph for Quadratic Review ! Q13 Job 26 Graph y = -x2 + 6x for the interval 0 <x<6 on the graph At what time is the ball at its greatest height?

5 What would be the maximum height?
Quadratic Review ! Q14 Job 26 A museum entrance way f(x) = -x Sketch the graph from 0<x<20 What would be the maximum height?

6 THINK PAIR SHARE Work together to complete Job 26 Think on your own
Pair up to see if partners answers share the same answer

7 Job 26 Due Wednesday Mar 29 Test Friday Unit 6
1) Counts as a take home test 2) Must show all work 3) No Lates 4) Complete in class 5) Stay after from 3-5 in 6) Library if help is needed Test Friday Unit 6


Download ppt "Problem of the Day! Q12 Job 26 Monday Mar 27"

Similar presentations


Ads by Google