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Tautology Decision May be able to use unateness to simplify process

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1 Tautology Decision May be able to use unateness to simplify process
Unate Function – one that has either the uncomplemented or complemented literals for each variable Function F is weakly unate with respect to the variable Xi when there is a variable Xi and at least one constant a  Pi satisfying F(|Xi = a)  F (X1 , , Xi , , Xn ) The SOP F is weakly unate with respect to the variable Xi when in an array F there is a sub-array of cubes that depend on Xi and in this sub-array all the values in a column are 0.

2 Weakly Unate SOP F Example
c3 and c4 depend on variable X1 first column of c3 and c4 are all 0. Therefore F is weakly unate with respect to the variable X1 X1 X X3 1111 – 1110 – c1 1111 – 1101 – c2 0110 – 0110 – c3 0101 – 0111 – c4 F =

3 Tautology Decision - Weakly Unate Simplification Theorems
Let an SOP F be weakly unate with respect to the variable Xj. Among the cubes of F, let G be the set of cubes that do not depend on the variable Xj. Then, G  1  F  1. Theorem 9.7 Let c1 = XjSA and c2 = XjS B where SA  SB = Pj and SA  SB =  Then, F  1  F(|c1)  1 and F(|c2)  1.

4 Tautology Decision Algorithm
If F has a column with all 0’s, then F is not a tautology. Let F = {c1,c2 , ,ck}, where ci is a cube. If the sum of the number of minterms in all cubes ci is less the total number in the univeral, cube then F is not a tautology. If there is a cube with all 1’s in F, then F is a tautology. When we consider only the active columns in F, if they are all two-valued, and if the number of variables is less than 7, then decide the tautology of F by the truth table.

5 Tautology Decision Algorithm (continued)
When there is a weakly unate variable, simplify the problem by using Theorem 9.6 When F consists of more than one cube: F is a tautology iff F(|c1)  1 and F(|c2)  1 where c1 = XjSA and c2 = XjS , SA  SB = Pj and SA  SB =  .

6 Tautology Decision Examples: G =
01 – 100 – 1100 11 – 111 – 0010 Examples: X3 variable has column with all 0’s, so not a tautology. F does not depend on X1. Let c1= ( ) and c2= ( ) By Thm 9.7, F is a tautology. G = 11 – 110 – 1110 11 – 110 – 0001 11 – 001 – 1111 F= 11 – 111 – 1110 11 – 111 – 0001 11 – 111 – 1111 F1= F(|c1) =  1 11 – 111 – 1111 F2= F(|c2) =  1

7 Generation of Prime Implicants
Definitions: Prime Implicant - an implicant contained by no other implicant. A set of prime implicants for a function F is denoted by PI(F ) Strongly Unate - Let X be a variable that takes a value in P={0, 1, 2, …, p-1}. If there a total order () on the values of variable X in function F, such that j  k ( j, k  P) implies F(| X = j)  F(| X = k), then the function F is strongly unate with respect to X. If F is strongly unate with respect to all the variables, then the function F is strongly unate.

8 Generation of Prime Implicants
Definitions: Strongly Unate – Next, assume that F is an SOP. If there is a total order () among the values of variable X, and if j  k ( j, k  P), then each product term of the SOP F(| X = j) is contained by all the product term of the SOP F(| X = k). In this case the SOP F is strongly unate with respect to X. If F is strongly unate with respect to Xi, then F is weakly unate with respect to Xi.

9 Strongly Unate Example
1111 – 1001 0111 – 0111 0011 – 0110 0001 – 0101 F(|X2= 0) = (1111 – 1111) F(|X2= 1) = F(|X2= 2) = F(|X2= 3) = F(|X2= 2) < F(|X2= 1) < F(|X2= 0) = F(|X2= 3) F = F(|X1= 0) = (1111 – 1001) F(|X1= 1) = F(|X1= 2) = F(|X1= 3) = F(|X1= 0) < F(|X1= 1) = F(|X1= 2) = F(|X1= 3) F is strongly unate with respect to X1 and to X2 0111 – 1111 0011 – 1111 0001 – 1111 1111 – 1001 1111 – 0111 1111 – 1001 1111 – 0111 1111 – 0110 0111 – 1111 0011 – 1111 1111 – 1001 1111 – 0111 1111 – 0110 1111 – 0101 1111 – 1111 0111 – 1111 0001 – 1111

10 Generation of Prime Implicants
Generation of Prime Implicants Algorithm

11 Generation of Prime Implicants
Example:

12 Generation of Prime Implicants
Example:

13 Generation of Prime Implicants
Example:

14 Sharp Operation Sharp Operation: (#) Used to computer F  G, assume For 2-valued inputs and F = U, n-variable function generates  (3n / n) prime implicants, so sharp function time consuming. Disjoint Sharp Operation: ( # ) Used to compute F  G. Cubes are disjoint, n-variable function has at most 2n cubes.

15 Sharp Operation

16 Sharp Operation

17 Sharp Operation Example:

18 Sharp Operation Example:

19 Sharp Operation Example:

20 Sharp Operation Example:


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