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Finding Limits Graphically and Numerically

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Presentation on theme: "Finding Limits Graphically and Numerically"β€” Presentation transcript:

1 Finding Limits Graphically and Numerically

2 To sketch graph, we need to know what’s going on at π‘₯=1.
Ex 𝑓 π‘₯ = π‘₯ 2 βˆ’3π‘₯+2 π‘₯βˆ’1 To sketch graph, we need to know what’s going on at π‘₯=1. We can use a table: π‘₯ approaches 1 from the left. π‘₯ approaches 1 from the right. π‘₯ 0.75 0.9 0.99 0.999 1 1.001 1.01 1.1 1.25 𝑓(π‘₯) 𝑓(π‘₯) approaches βˆ’1. 𝑓(π‘₯) approaches βˆ’1.

3 From the table, we see that 𝑓 π‘₯ approaches βˆ’1 as π‘₯ gets closer to 1.
We can verify that by looking at the graph of 𝑓(π‘₯).

4 This leads us to the definition of the limit.
Def: We write lim π‘₯β†’π‘Ž 𝑓 π‘₯ =𝐿 and say β€œthe limit of 𝑓(π‘₯) as π‘₯ approaches π‘Ž is 𝐿” if we can make the values of 𝑓 π‘₯ as close to 𝐿 as we want by taking π‘₯ to be close to π‘Ž (but not equal to π‘Ž) on both sides of a.

5 Three Cases to Consider:
Remark: lim π‘₯β†’π‘Ž 𝑓 π‘₯ =𝐿 in all three cases.

6 The limit is reinforced by the graph of 𝑓.
Ex 2. Create a table of values for the function and use the result to estimate lim π‘₯β†’0 π‘₯ π‘₯+1 βˆ’1 π‘₯ 𝑓(π‘₯) The limit is reinforced by the graph of 𝑓.

7 Ex 3. Find the limit of 𝑓(π‘₯) as π‘₯ approaches 2, where
𝑓 π‘₯ = 1, π‘₯β‰ 2 0, π‘₯=2 Remark: The existence or non-existence of 𝑓(π‘₯) at π‘₯=π‘Ž has no bearing on the existence of the limit of 𝑓(π‘₯) as π‘₯ approaches 𝑐.

8 LIMITS THAT FAIL TO EXIST
Ex 4. Show that the limit does not exist. Remark: The limit fails to exist due to different left and right behavior.

9 lim π‘₯β†’ π‘₯ 2 Ex 5. Discuss the existence of the limit Remark: The limit fails to exist due to unbounded behavior.

10 lim π‘₯β†’0 sin 1 π‘₯ Ex 6. Discuss the existence of the limit Remark: The limit fails to exist due to oscillating behavior.

11 So, in summary (from Ex. 4-6), limits fail to exist in three situations:
Different left and right behavior Unbounded behavior Oscillating behavior


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