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WELCOME TO THE HIGHER MATHEMATICS CLASS

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Presentation on theme: "WELCOME TO THE HIGHER MATHEMATICS CLASS"β€” Presentation transcript:

1 WELCOME TO THE HIGHER MATHEMATICS CLASS
SHIPAN CHANDRA DEBNATH ASSISTANT PROFESSOR & HEAD OF THE DEPARTMENT DEPARTMENT OF MATHEMATICS CHITTAGONG CANTONMENT PUBLIC COLLEGE

2 DIFFERENTIATION Today`s Topics is Chapter - 9 Exercise -9(C)
Book: Higher Mathematics Axorpotra Publications

3 Learning Outcomes After complete this chapter students can
Explain Different Formula of Differentiation Derivative of function of Function

4 Different Formulae of Derivative:
1. 𝑑(𝑐) 𝑑π‘₯ = 𝑑(π‘₯) 𝑑π‘₯ =1 3. 𝑑(π‘₯𝑛) 𝑑π‘₯ =𝑛π‘₯π‘›βˆ’ 𝑑(𝑒π‘₯) 𝑑π‘₯ =ex 5. . 𝑑(π‘Žπ‘₯) 𝑑π‘₯ =π‘Žπ‘₯ lna 𝑑(οƒ–π‘₯) 𝑑π‘₯ = 1 2οƒ–π‘₯ 7. . 𝑑(𝑙𝑛π‘₯) 𝑑π‘₯ = 1 π‘₯ 𝑑(π‘™π‘œπ‘”π‘Žπ‘₯) 𝑑π‘₯ = 1 π‘₯ π‘™π‘œπ‘”π‘Žπ‘’

5 9. . 𝑑(𝑠𝑖𝑛π‘₯) 𝑑π‘₯ =π‘π‘œπ‘ π‘₯ 10. 𝑑(π‘π‘œπ‘ π‘₯) 𝑑π‘₯ =βˆ’π‘ π‘–π‘›π‘₯ 11. . 𝑑(π‘‘π‘Žπ‘›π‘₯) 𝑑π‘₯ =𝑠𝑒𝑐2π‘₯ 12. . 𝑑(π‘π‘œπ‘‘π‘₯) 𝑑π‘₯ =βˆ’cosec2x 13. . 𝑑(𝑠𝑒𝑐π‘₯) 𝑑π‘₯ =secxtanx 14.. 𝑑(π‘π‘œπ‘ π‘’π‘π‘₯) 𝑑π‘₯ =βˆ’π‘π‘œπ‘ π‘’π‘π‘₯π‘π‘œπ‘‘π‘₯

6 GROUP WORK 1.Find the differentiation of the following functions w.r.to x i.sin2x ii. Cos3x iii.Tan5x iv.cot7x v.cosec7x

7 vi. (ax2+bx+c) vii. xsinx viii. tanex2 ix.ln(sinx2) x.sin2[ln(secx)]

8 EVALUATION Tell me the First Principle of Derivative why the derivative of constant is 0?

9 HOME WORK 1.Find the differentiation of the following functions w.r.to x i. sin2[ln(x2)] ii. e5lntan5x iii.x0cosx0 iv. π‘‘π‘Žπ‘›π‘₯βˆ’π‘π‘œπ‘‘π‘₯ π‘‘π‘Žπ‘›π‘₯+π‘π‘œπ‘‘π‘₯ v.sinln{cosec7x}

10 THANKS TO ALL, DEAR STUDENT Sir Issac Newton, Father of Calculus


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