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1A + 2B 1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with mL 2.5 M B. Kc = 2.0 x 10-10
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Drill: 1A + 2B 1C + 1D Calculate the equilibrium concentrations of each species when a solution is made with 1.0 M A & 1.0 M B. Kc = 2.0 x 10-12
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Exp # [A] [B] [C] Rate 1) 27 C 2) 27 C 3) 27 C 4) 27 C 5)127 C
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([A4]/[A1])a = rate4/rate1
Exp # [A] [B] [C] Rate 1) 27 C 2) 27 C 3) 27 C 4) 27 C 5)127 C ([A4]/[A1])a = rate4/rate1 3a = 9; thus, a = 2
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([B3]/[B2])b = rate3/rate2
Exp # [A] [B] [C] Rate 1) 27 C 2) 27 C 3) 27 C 4) 27 C 5)127 C ([B3]/[B2])b = rate3/rate2 2b = 8; thus b = 3
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([C2]/[C1])c = rate2/rate1
Exp # [A] [B] [C] Rate 1) 27 C 2) 27 C 3) 27 C 4) 27 C 5)127 C ([C2]/[C1])c = rate2/rate1 2c = 2; thus c = 1
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Rate = k[A]2[B]3[C] k = Rate [A]2[B]3[C]
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1 P2 + 2 SO2 + 1 O2 2 PO2 + 2 SO 2 PO2 1 P2O4 1 P2O SO 2 PO + 2 SO2 4 PO SO2 2 P2O5 + 3 S 3 P2O S 1 P6S6O15
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1 P2 + 2 SO2 + 1 O2 2 PO2 + 2 SO 2 PO2 1 P2O4 1 P2O SO 2 PO + 2 SO2 4 PO SO2 2 P2O5 + 3 S 3 P2O S 1 P6S6O15
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1 P2 + 2 SO2 + 1 O2 2 PO2 + 2 SO 2 PO2 1 P2O4 2 P2O SO 4 PO + 4 SO2 4 PO SO2 2 P2O5 + 3 S 3 P2O S 1 P6S6O15
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1 P2 + 2 SO2 + 1 O2 2 PO2 + 2 SO 4 PO2 2 P2O4 2 P2O SO 4 PO + 4 SO2 4 PO SO2 2 P2O5 + 3 S 3 P2O S 1 P6S6O15
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2 P2 + 4 SO2 + 2 O2 4 PO2 + 4 SO 4 PO2 2 P2O4 2 P2O SO 4 PO + 4 SO2 4 PO SO2 2 P2O5 + 3 S 3 P2O S 1 P6S6O15
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2 P2 + 4 SO2 + 2 O2 4 PO2 + 4 SO 4 PO2 2 P2O4 2 P2O SO 4 PO + 4 SO2 4 PO SO2 2 P2O5 + 3 S 3 P2O S 1 P6S6O15
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2 P2 + 4 SO2 + 2 O2 4 PO2 + 4 SO 4 PO2 2 P2O4 2 P2O SO 4 PO + 4 SO2 4 PO SO2 2 P2O5 + 3 S 2 P2 + 3 SO2 + 2 O2 2 P2O5 + 3 S
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2 P2 + 3 SO2 + 2 O2 2 P2O5 + 3 S Rate = k[P2 ]2[SO2]3[O2]2
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__N2 +__CO2 +__O2 __NO2 +__CO
__NO2 __N2O4 __N2O __CO __NO +__CO2 __ NO __ CO2 __ N2O5 + __ C __N2O __C __C2N2O5
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__N2 +__CO2 +__O2 __NO2 +__CO
__NO2 __N2O4 __N2O __CO __NO +__CO2 4 NO CO2 2 N2O5 + 3 C __N2O __C __C2N2O5
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__N2 +__CO2 +__O2 __NO2 +__CO
__NO2 __N2O4 2 N2O CO 4 NO +4 CO2 4 NO CO2 2 N2O5 + 3 C __N2O __C __C2N2O5
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__N2 +__CO2 +__O2 __NO2 +__CO
__NO2 __N2O4 2 N2O CO 4 NO +4 CO2 4 NO CO2 2 N2O5 + 3 C __N2O __C __C2N2O5
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__N2 +__CO2 +__O2 __NO2 +__CO
4 NO2 2 N2O4 2 N2O CO 4 NO +4 CO2 4 NO CO2 2 N2O5 + 3 C __N2O __C __C2N2O5
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__N2 +__CO2 +__O2 __NO2 +__CO
4 NO2 2 N2O4 2 N2O CO 4 NO +4 CO2 4 NO CO2 2 N2O5 + 3 C __N2O __C __C2N2O5
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2 N2 + 4 CO2 + 2 O2 4 NO2 + 4 CO 4 NO2 2 N2O4 2 N2O CO 4 NO +4 CO2 4 NO CO2 2 N2O5 + 3 C __N2O __C __C2N2O5
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2 N2 + 4 CO2 + 2 O2 4 NO2 + 4 CO 4 NO2 2 N2O4 2 N2O CO 4 NO +4 CO2 4 NO CO2 2 N2O5 + 3 C 2 N2 + 3 CO2 + 2 O2 2 N2O5 + 3 C __N2O __C __C2N2O5
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2 N2 + 4 CO2 + 2 O2 4 NO2 + 4 CO 4 NO2 2 N2O4 2 N2O CO 4 NO +4 CO2 4 NO CO2 2 N2O5 + 3 C 2 N2 + 3 CO2 + 2 O2 2 N2O5 + 3 C 2 N2O C 2 C2N2O5
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2 N2 + 4 CO2 + 2 O2 4 NO2 + 4 CO 4 NO2 2 N2O4 2 N2O CO 4 NO +4 CO2 4 NO CO2 2 N2O5 + 3 C 2 N2 + 3 CO2 + 2 O2 2 N2O5 + 3 C 2 N2O C 2 C2N2O5
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Acid/Base
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Properties of Acids Sour taste, Change color of dyes, Conduct electricity in solution, React with many metals, React with bases to form salts
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Properties of Bases Bitter taste, Feel slippery, Change color of dyes, Conduct electricity in solution, React with acids to form salts
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Arrhenius Acids: release H+ or H3O+ in solution
Bases: release OH- in solution
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Arrhenius Acid: HA --> H+ + A- HCl --> H+ + Cl-
Base: MOH --> M+ + OH- NaOH -->Na+ + OH-
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Bronsted-Lowry Acid: Proton donor Base: Proton Acceptor
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Bronsted-Lowry HA + H2O --> H3O+ + A- HI + H2O --> H3O+ + I-
Acid Base CA CB NH3 + H2O --> NH4+ + OH- Base Acid CA CB
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Lewis Acid/Base Acid: Electron Acceptor Base: Electron Donor
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Lewis Acid/Base H3N: + BF3 --> H3N-BF3 Base Acid Neutral
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Common Names H+ Hydrogen ion H3O+ Hydronium ion H- Hydride ion
OH- Hydroxide ion NH3 Ammonia NH4+ Ammonium ion
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Amphiprotism Can act like an acid or a base
Can donate or accept protons
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Naming Acids All acids are H-anion If the anion is:
-ides hydro___ic acids -ates ___ic acids -ites ___ous acids
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Naming Bases Almost all bases are metal hydroxides
Name by normal method Ammonia (NH3) as well as many amines are bases
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Strong Acids or Bases Strong acids or bases ionize 100 % in solution
Weak acids or bases ionize <100 % in solution
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Drill: Name each of the following: KOH HBr Al(OH)3 H2CO3 HClO4 NH3
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Review Drill & Check HW
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CHM II HW Review PP-21 Complete the attached assignment & turn it in tomorrow.
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Strong Acids or Bases Strong acids or bases ionize 100 % in solution
Weak acids or bases ionize <100 % in solution
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Strong Acids HClO4 Perchloric acid H2SO4 Sulfuric acid
HNO3 Nitric acid HCl Hydrochloric acid HBr Hydrobromic acid HI Hydroiodic acid
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Strong Bases All column I hydroxides Ca(OH)2 Calcium hydroxide
Sr(OH)2 Strontium hydroxide Ba(OH)2 Barium hydroxide
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Strong Acid/Base Ionizes 100 % (1 M) HA H+ + A- 1 M – all
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Binary Acids Acids containing only 2 elements HCl Hydrochloric acid
H2S Hydrosulfuric acid
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Ternary Acids H2SO4 Sulfuric acid HNO3 Nitric acid
Acids containing 3 elements H2SO4 Sulfuric acid HNO3 Nitric acid
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Monoprotic Acids Acids containing only one ionizable hydrogen
HBr Hydrobromic acid HC2H3O2 Acetic acid
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Diprotic Acids Acids containing 2 ionizable hydrogens
H2SO4 Sulfuric acid H2CO3 Carbonic acid
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Triprotic Acids Acids containing 3 ionizable hydrogens
H3PO4 Phosphoric acid H3AsO4 Arsenic acid
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Polyprotic Acids H4SiO4 Silicic acid H2CO2 Carbonous acid
Acids containing more than one ionizable hydrogens H4SiO4 Silicic acid H2CO2 Carbonous acid
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Monohydroxic Base A base containing only one ionizable hydroxide
NaOH Sodium hydroxide LiOH Lithium hydroxide
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Neutralization Rxn HA(aq) + MOH(aq) MA(aq) + H2O(l)
A reaction between an acid & a base making salt & H2O HA(aq) + MOH(aq) MA(aq) + H2O(l)
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Neutralization Rxn HCl(aq) + NaOH(aq) NaCl(aq) + H2O(l)
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pH The negative log of the hydrogen or hydronium ion concentration
pH = -log[H+] pOH = -log[OH-]
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Calculate the pH of each of the following: 1) [H+] = 0
Calculate the pH of each of the following: 1) [H+] = M 2) [HCl] = M 3) [HBr] = M
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Calculate the pOH of each of the following:
1) [OH-] = M 2) [KOH] = M 3) [NaOH] = 4.0 x 10-7 M
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A solution with known concentration
Standard Solution A solution with known concentration
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Drill: Identify: acid, base, CA, & CB
HCO3- + H2O H2CO3 + OH-
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Review Drill & Check HW
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CHM II HW Review PP-21 Complete the attached assignment & turn it in tomorrow.
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Titration A method of determining the concentration of one solution by reacting it with a standard solution
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Titration Formula for monoprotic solutions
MAVA = MBVB
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Equivalence Point The point where the concentrations of the two solutions in the titration are equal
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Titration Fact When titrating acids against bases, the end
point of the titration is at the equivalence point
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Acid/Base Equivalence Point
The point where the H+ concentration is equal to the OH- concentration
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Titration Fact No changes will be observed when titrating acids against bases; thus, one must use an indicator to see changes
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Indicator An organic dye that changes color when the pH changes
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Drill: Calculate the molarity of 25.0 mL HCl when it’s titrated to its equivalence point with 50.0 mL M NaOH
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Titration Formula for monoprotic solutions
MAVA = MBVB
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Dilution Formula M1V1 = M2V2
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Calculate the mL of 16.0 M HNO3 it takes to make 4.0 L of 0.100 M HNO3
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Calculate the mL of 12.5 M HCl required to make 2.5 L of 0.200 M HCl
Make Calculations Calculate the mL of 12.5 M HCl required to make 2.5 L of M HCl
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Moles of solute per liter of solution (M)
Molarity Moles of solute per liter of solution (M)
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Normality Number of moles of hydrogen or hydroxide ions per liter of solution (N)
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Titration Formula for Acid/Base
NAVA = NBVB Elliott’s Rule: #HMAVA = #OHMBVB
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Make Calculations Calculate the molarity of 30.0 mL H2CO3 when it’s titrated to its equivalence point with 75.0 mL M NaOH
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Make Calculations Calculate the molarity of 40.0 mL H3PO4 when it’s titrated to its equivalence point with 30.0 mL 0.20 M Ba(OH)2
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Calculate the volume of 0. 250 M HCl needed to titrate 50. 00 mL 0
Calculate the volume of M HCl needed to titrate mL M NaOH to its equivalence point
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Calculate the molarity 25. 0 mL H3PO4 that neutralizes 50. 00 mL 0
Calculate the molarity 25.0 mL H3PO4 that neutralizes mL M Ca(OH)2 to its equivalence point
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Titration Curve: Strong acid vs strong base
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Titration Curve: Strong acid vs strong base; then weak acid vs strong base
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Titration Curve: Strong base vs strong acid; then weak base vs strong acid
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3.2 g HI is dissolved in a 1250 mL aqueous solution. Calculate its pH.
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Calculate the volume of 0. 10 M H3PO4 that neutralizes 50. 00 mL 0
Calculate the volume of 0.10 M H3PO4 that neutralizes mL M Ca(OH)2 to its equivalence point
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AP CHM HW Read: Chapter 13 Problems: 7 & 9 Page: 395
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CHM II HW Read: Chapter 18 Problems: 27 Page: 787
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Drill: Calculate the molarity of 25
Drill: Calculate the molarity of mL of H3PO4 that was titrated to its equivalence point with mL of M Ba(OH)2.
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