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Difference of Two Squares
The figure shows a square of side a. a a b a b A smaller square of side b is cut out from it. Area of the remaining L-shape = area of the larger square – area of the smaller square = a2 – b2
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a b Area = a2 – b2 We can divide the remaining L-shape into two rectangles (I and II), and use them to form another rectangle. a b I I II II
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What is the length of the new rectangle? a + b
II I II width? length? What is the length of the new rectangle? a + b What is the width of the new rectangle? a – b What is the area of the new rectangle? (a + b)(a – b)
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Can you set up an identity in terms of a and b?
II a – b a + b Area = a2 – b2 Area = (a + b)(a – b) By comparing the areas, we can set up an important algebraic identity: It is known as the identity of the difference of two squares.
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Let’s prove this identity algebraically.
R.H.S. = (a + b)(a – b) = (a + b)a – (a + b)b = a2 + ba – ab – b2 = a2 – b2 L.H.S. = a2 – b2
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Expand the following expressions by using the identity of the difference of two squares.
(h + 1)(h – 1) (2x – 3y)(2x + 3y)
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Follow-up question Expand the following expressions by using the identity of the difference of two squares. (a) (xy + 4)(xy – 4) (b) (3z – 8cd)(3z + 8cd) Solution
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