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6.6 Finding Segment Lengths.

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Presentation on theme: "6.6 Finding Segment Lengths."— Presentation transcript:

1 6.6 Finding Segment Lengths

2 ab = cd Chord-Chord Rule: Two chords intersect INSIDE the circle a d c

3 Example 1: 9 12 6 3 x x 2 2 x = 3 x = 8 x 3 6 2 x = 1

4 Example 2: Find x 2x  3x = 12  8 8 12 2x 3x 6x2 = 96 x2 = 16 x = 4

5 Secant-Secant Rule: OW-OW

6 EA • EB = EC • ED Two secants intersect Secant-Secant Rule:
OUTSIDE the circle Secant-Secant Rule: E A B C D EA • EB = EC • ED

7 x = 31 7 (7 + 13) = 4 (4 + x) 140 = 16 + 4x 124 = 4x Example 3: B 13 A
C x D 7 (7 + 13) = 4 (4 + x) x = 31 140 = x 124 = 4x

8 x = 11.8 x 5 8 6 6 (6 + 8) = 5 (5 + x) 84 = 25 + 5x 59 = 5x Example 4:
B x A 5 D 8 6 C E 6 (6 + 8) = 5 (5 + x) x = 11.8 84 = x 59 = 5x

9 When A secant and tangent originate from the same
Secant-Tangent Rule: When A secant and tangent originate from the same point OUTSIDE the circle, use O ●W = O ●W.

10 Notice that on the tangent segment, the outside is the whole!
Secant Segment External Segment Tangent Segment

11 A secant and tangent originate from the same point
Secant-Tangent Rule: A secant and tangent originate from the same point OUTSIDE the circle C B E A EA2 = EB • EC

12 Example 5: C B x 12 E 24 A 242 = 12 (12 + x) x = 36 576 = x

13 Example 6: 5 B E 15 C x A x2 = 5 (5 + 15) x = 10 x2 = 100

14 Given two chords, USE Given two secants OR a tangent and a secant, USE
What you should know by now… Given two chords, USE Given two secants OR a tangent and a secant, USE


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