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6-2 Substitution Again Goals: Solve linear systems using substitution

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Presentation on theme: "6-2 Substitution Again Goals: Solve linear systems using substitution"— Presentation transcript:

1 6-2 Substitution Again Goals: Solve linear systems using substitution
Interpret solutions to special problems Eligible Content: A / A

2 Practice Complete worksheet – “Monstrous Mammal”

3 Special Problems No solution Many solutions
There is no point in common All variables will cancel out You will be left with a false statement: 4 = 12 Many solutions There are many points in common You will be left with a true statement: 5 = 5

4 Examples 3x + y = –1 –9x – 3y = 3 many solutions x – 2y = 5
no solution 4x + 4y = –8 x + y = –2 many solutions 2x + y = –1 –6x – 3y = –15 no solution

5 Practice (not all problems are special)
x – 2y = 1 –2x + 4y = 10 x – 3y = –24 5x + 8y = –5 6x + y = 14 12x + 2y = 28 No solution (-9, 5) Many solutions

6 Homework Page 347 #14-19


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