1. The Mirror Equation
and Ray Diagrams

2. object
distance
image
distance
focal
length

3. I look in a mirror with a focal length of 20 cm at arms length, 70 cm away. Where would the image of my eyeball form? Is it real or virtual?
f = .2 m
1/p + 1/q = 1/f
p = .7 m
1/q = 1/f – 1/p
1/q = 1/.2m – 1/.7m
1/q = 3.57 m-1
q = .28 m
A real image… it is positive

4. Ray Diagrams f = .2m C = .4m 1. Parallel rays go thru f
2. Thru f goes parallel
3. Thru C bounces back

5. q = 4 m ?
f = 10 m
C = 20 m
p = 3 m
1/f - 1/p = 1/q
1/10 m- 1/3m = m-1
q = -4.29