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5-1 Bisectors, Medians, and Altitudes
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Perpendicular Bisector- line/segment that has the midpoint of the side and is perpendicular to it
Altitude D D is the midpoint of BC.
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Theorems 5.1: Any point on the perpendicular bisector of a segment is equidistant from the endpoints of the segment. 5.2: Any point equidistant from the endpoints of a segment lies on the perpendicular bisector of the segment.
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Point of concurrency: The point of intersection.
Concurrent lines: When three or more lines intersect at a common point. Point of concurrency: The point of intersection. Circumcenter: The point of concurrency of the perpendicular bisectors of a triangle Theorem 5.3: The circumcenter of a triangle is equidistant from the vertices of the triangle. Point of Concurrency Called circumcenter if the lines are perpendicular bisectors.
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Points on Angle Bisectors
Theorem 5.4: Any point on the angle bisector is equidistant from the sides of the angle. Theorem 5.5: Any point equidistant from the sides of an angle lies on the angle bisector.
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Incenter Incenter: The intersection point of the angle bisectors of a triangle. Theorem 5.6: (Incenter Theorem): The incenter of a triangle is equidistant from each side of the triangle.
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Median: A segment whose endpoints are a vertex of the triangle and the midpoint of the side opposite of the vertex. E N G F In EFG, FN is a median. Find EN if EG = 11 FN is the median. So, N is the midpoint of EG. Since EG = 11, EN = ½ · 11 or 5.5.
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Centroid: When the medians of a triangle intersect at a common point.
K Q M R P X J X is the centroid of JKM JR, KP, and MQ are concurrent Centroid Theorem (5.7): The centroid of a triangle is located two thirds of the distance from a vertex to the midpoint of the side opposite the vertex on a median.
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Check your progress Try page 272 #2 (check your progress)
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Altitudes Altitude: A perpendicular segment with one endpoint at a vertex and the other on the opposite side. Orthocenter: The point of concurrency of the altitudes. A B C Altitude Orthocenter
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Altitude Examples Altitude Right angle
The altitude is a side of the triangle. Acute angle The altitude is inside the triangle. Altitude Altitude Obtuse angle The altitude is outside the triangle.
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EXAMPLE In RST, RP and SQ are medians. If RQ=7x-1, SP=5x-4, and QT=6x+9, find PT. Since RP and SQ are medians, Q and P are midpoints. Use the given values for RQ and QT to first solve for x. RQ = QT 7x - 1 = 6x + 9 7x = 6x 7x = 6x + 10 7x - 6x = 6x x x = 10 Next, use the values of x and SP to find PT. SP = PT 5x - 4 = PT 5(10) – 4 = PT 46 = PT R S T P Q
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In RST, RQ, SP, and OT are medians. Find AQ if RA = 6. Since RA = 6,
RA = 2/3 (RQ) 6 = 2/3 (RQ) (3/2) (6) = RQ 9 = RQ so AQ = 3 If OA = 2.4, what is OT? Since OA = 2.4, AT = 2.4 x 2 = 4.8 So OT = = 7.2 R S T O P Q A Use the Centroid Theorem (5.7): The centroid of a triangle is located two thirds of the distance from a vertex to the midpoint of the side opposite the vertex on a median.
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Y Z X E The line containing YE is the perpendicular bisector of XZ.
YE is an altitude. E is the midpoint of XZ.
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