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CIRCUITS Current Resistance Ohms Law Power Series Circuits

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Presentation on theme: "CIRCUITS Current Resistance Ohms Law Power Series Circuits"— Presentation transcript:

1 CIRCUITS Current Resistance Ohms Law Power Series Circuits
Parallel Circuits Combination Circuits

2 Electric Current Rate of Flow of Electric Charge through a conductor.
Unit of electric current: the ampere, A A = 1 C/s.

3 Drift Velocity

4 Resistance The ratio of voltage to current is called the resistance:
Slows the flow of electric charge 1V/A = 1 Ω (Ohms)

5 Resistance The Resistance of a wire: Is Characteristic of the material
(resisitivity) Is Directly proportional to Length L↑, Ω↑ Is Inversely proportional to Area. A↑ , Ω↓ Increases with temperature T↑, Ω↑

6 𝑉=𝐼𝑅 Ohm’s Law Potential Current Resistance ? 0.5A 12Ω 12V 4Ω 6V 1.5A
Magic Triangle

7 Power Rate at which work is done 𝑃=𝐼𝑉=𝐼2𝑅 = 𝑉2 𝑅
𝑃= 𝑊𝑜𝑟𝑘 𝑡 →𝑉= 𝑊𝑜𝑟𝑘 𝑄 →𝑊𝑜𝑟𝑘=𝑄𝑉 𝑃= 𝑊𝑜𝑟𝑘 𝑡 = 𝑄𝑉 𝑡 = 𝑄 𝑡 𝑉 → 𝑃=𝐼𝑉 𝑃=𝐼𝑉=𝐼 𝐼𝑅 =𝐼2𝑅 𝑃=𝐼𝑉= 𝑉 𝑅 𝑉= 𝑉2 𝑅 𝑃=𝐼𝑉=𝐼2𝑅 = 𝑉2 𝑅 Magic Circle

8 Power 12V ? 0.5A 4Ω 0.75A 4V 2Ω 𝑃=𝐼𝑉=𝐼2𝑅 = 𝑉2 𝑅 Potential Resitance
Current Power 12V ? 0.5A 0.75A 4V

9 Power The electric company measures kilowatt hours → kWh
kWh = power * time = Work Work required to keep your household running. 1 kWh= 1000W * 3600s = 3.6*106 J

10 Resistors in Series 𝑉=𝑉1+𝑉2+𝑉3 𝑉=𝐼𝑅1+𝐼𝑅2+𝐼𝑅3 𝑉=𝐼 𝑅1+𝑅2+𝑅3 𝑉=𝐼𝑅 𝑒𝑞
A series connection has a single path from the battery, through each circuit element in turn, then back to the battery. The sum of the voltage drops across the resistors equals the battery voltage. The current through each resistor is the same. Voltage across each resistor is different 𝑉=𝑉1+𝑉2+𝑉3 𝑉=𝐼𝑅1+𝐼𝑅2+𝐼𝑅3 𝑉=𝐼 𝑅1+𝑅2+𝑅3 𝑉=𝐼𝑅 𝑒𝑞 𝑹𝒆𝒒=𝑹𝟏+𝑹𝟐+𝑹𝟑

11 Resistors in Series Determine the following:
Equivalent Resistance of the circuit Current through the resistors Voltage Drop across each resistor Power dissipated by each resistor Power dissipated by the entire circuit 6V

12 Resistors in Series Determine the following:
Equivalent Resistance of the circuit Current through the resistors Voltage Drop across each resistor Power dissipate by each resistor Power dissipate by the entire circuit

13 1 𝑅𝑒𝑞 = ( 1 𝑅1 + 1 𝑅2 + 1 𝑅3 ) Resistors in Parallel 𝐼=𝐼1+𝐼2+𝐼3
A parallel connection splits the current The voltage across each resistor is the same Current across each resistor is different. 𝐼=𝐼1+𝐼2+𝐼3 𝑉 𝑅𝑒𝑞 = 𝑉 𝑅1 + 𝑉 𝑅2 + 𝑉 𝑅3 𝑉 𝑅𝑒𝑞 =𝑉( 1 𝑅1 + 1 𝑅2 + 1 𝑅3 ) 1 𝑅𝑒𝑞 = ( 1 𝑅1 + 1 𝑅2 + 1 𝑅3 )

14 Resistors in Parallel Determine the following:
12V Resistors in Parallel Determine the following: Equivalent Resistance of the circuit Current through the circuit Current across each resistor Power dissipated by each resistor Power dissipated by the entire circuit

15 Resistors in Parallel Determine the following:
Equivalent Resistance of the circuit Current through the circuit Current across each resistor Power dissipated by each resistor Power dissipated by the entire circuit

16 Complex Circuits Determine the following:
Equivalent Resistance of the circuit Current through the resistors Voltage Drop across each resistor Power dissipate by each resistor Power dissipate by the entire circuit

17 Complex Circuits Determine the following:
Equivalent Resistance of the circuit Current through the resistors Voltage Drop across each resistor Power dissipate by each resistor Power dissipate by the entire circuit

18 Complex Circuits Determine the following:
Equivalent Resistance of the circuit Current through the resistors Voltage Drop across each resistor Power dissipate by each resistor Power dissipate by the entire circuit


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