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Section 13.6 The Normal Curve
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What You Will Learn Rectangular Distribution J-shaped Distribution
Bimodal Distribution Skewed Distribution Normal Distribution z-Scores
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Rectangular Distribution
All the observed values occur with the same frequency.
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J-shaped Distribution
The frequency is either constantly increasing or constantly decreasing.
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Bimodal Distribution Two nonadjacent values occur more frequently than any other values in a set of data.
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Skewed Distribution Has more of a “tail” on one side than the other.
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Skewed Distribution Smoothing the histograms of the skewed distributions to form curves.
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Skewed Distribution The relationship between the mean, median, and mode for curves that are skewed to the right and left.
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Normal Distribution The most important distribution is the normal distribution.
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Properties of a Normal Distribution
The graph of a normal distribution is called the normal curve. The normal curve is bell shaped and symmetric about the mean. In a normal distribution, the mean, median, and mode all have the same value and all occur at the center of the distribution.
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Empirical Rule Approximately 68% of all the data lie within one standard deviation of the mean (in both directions). Approximately 95% of all the data lie within two standard deviations of the mean (in both directions). Approximately 99.7% of all the data lie within three standard deviations of the mean (in both directions).
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z-Scores z-scores (or standard scores) determine how far, in terms of standard deviations, a given score is from the mean of the distribution.
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z-Scores The formula for finding z-scores (or standard scores) is
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Example 2: Finding z-scores
A normal distribution has a mean of 80 and a standard deviation of 10. Find z-scores for the following values. a) 90 b) 95 c) 80 d) 64
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Example 2: Finding z-scores
Solution a) 90 A value of 90 is 1 standard deviation above the mean.
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Example 2: Finding z-scores
Solution b) 95 A value of 90 is 1.5 standard deviations above the mean.
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Example 2: Finding z-scores
Solution c) 80 The mean always has a z-score of 0.
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Example 2: Finding z-scores
Solution d) 64 A value of 64 is 1.6 standard deviations below the mean.
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To Determine the Percent of Data Between any Two Values
1. Draw a diagram of the normal curve indicating the area or percent to be determined. 2. Use the formula to convert the given values to z-scores. Indicate these z-scores on the diagram. 3. Look up the percent that corresponds to each z-score in Table 13.7.
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To Determine the Percent of Data Between any Two Values
a) When finding the percent of data to the left of a negative z-score, use Table 13.7(a).
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To Determine the Percent of Data Between any Two Values
b) When finding the percent of data to the left of a positive z-score, use Table 13.7(b).
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To Determine the Percent of Data Between any Two Values
c) When finding the percent of data to the right of a z-score, subtract the percent of data to the left of that z-score from 100%.
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To Determine the Percent of Data Between any Two Values
c) Or use the symmetry of a normal distribution.
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To Determine the Percent of Data Between any Two Values
d) When finding the percent of data between two z-scores, subtract the smaller percent from the larger percent.
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To Determine the Percent of Data Between any Two Values
4. Change the areas you found in Step 3 to percents as explained earlier.
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Example 5: Horseback Rides
Assume that the length of time for a horseback ride on the trail at Triple R Ranch is normally distributed with a mean of 3.2 hours and a standard deviation of 0.4 hour. a) What percent of horseback rides last at least 3.2 hours? Solution In a normal distribution, half the data are above the mean. Since 3.2 hours is the mean, 50%, of the horseback rides last at least 3.2 hours.
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Example 5: Horseback Rides
b) What percent of horseback rides last less than 2.8 hours? Solution Convert 2.8 to a z-score. The area to the left of –1.00 is The percent of horseback rides that last less than 2.8 hours is 15.87%.
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Example 5: Horseback Rides
c) What percent of horseback rides are at least 3.7 hours? Solution Convert 3.7 to a z-score. Area to left of 1.25 is = 89.44%. % above 1.25: 1 – 89.44% = 10.56%. Thus, 10.56% of horseback rides last at least 3.7 hours.
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Example 5: Horseback Rides
d) What percent of horseback rides are between 2.8 hours and 4.0 hours? Solution Convert 4.0 to a z-score. Area to left of 2.00 is = 97.22%. Percent below 2.8 is 15.87%. The percent of data between –1.00 and 2.00 is 97.22% – 15.87% = 81.58%.
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Example 5: Horseback Rides
Solution Thus, the percent of horseback rides that last between 2.8 hours and 4.0 hours is 81.85%.
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Example 5: Horseback Rides
e) In a random sample of 500 horseback rides at Triple R Ranch, how many are at least 3.7 hours? Solution In part (c), we determined that 10.56% of all horseback rides last at least 3.7 hours. Thus, × 500 = 52.8, or approximately 53, horseback rides last at least 3.7 hours.
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