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Algebra (Solving Equations)

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Presentation on theme: "Algebra (Solving Equations)"— Presentation transcript:

1 Algebra (Solving Equations)
Lesson # 41 Algebra (Solving Equations)

2 By Amanda Brown Of 803

3 Solving Algebra Equations
Suppose you have an equation like 3x + 1 = 7 What would be the value of “x” to make this a “TRUE” statement?

4 To find out the value of “x”
take the answer “7” and start working backwards.

5 Whatever you do to the left side, must also be done to the right side.
3x + 1 = 7 Get rid of the + 1 first, by subtracting it from the left side of the equation. Whatever you do to the left side, must also be done to the right side.

6 Therefore 3 times “x” must = 6.
So… subtract 1 from the 7 To leave you 6. Therefore 3 times “x” must = 6.

7 That means… “X” must Equal 2

8 Is a true mathematical statement…
See “ 3x + 1 = 7” Is a true mathematical statement… When X = 2

9 What is the value of “X” in this equation:
Another example… What is the value of “X” in this equation: (4x)2 = 64

10 4 times “x” has to be squared.
The answer to that must equal 64. Soooooo… Find the square root of 64… 8, right.

11 So, then … 4 times what give you 8? 2

12 So then … (4 x “2”)2 = 64

13 And now… 10 Practice Questions

14 For the next 10 questions…
Find the value of “X”.

15 Question # 1 X + 31 = 36

16 Question # 2 X + -3 = +7

17 Question # 3 (6 - 2) x = 40

18 Question # 4 3x + 4 = 7

19 Question # 5 ( 7 – x ) 2 = 9

20 Question # 6 8x + 3 = 27

21 Question # 7 x – = 9

22 Question # 8 (x + 6) 4 = 32

23 Question # 9 (4x)2 = 144

24 Question # 10 (9x) + 4 = 4

25 And Now.. The Answers Prepare Yourself !

26 Question # 1 X + 31 = 36 5

27 Question # 2 X + -3 = +7 +10

28 Question # 3 (6 - 2) x = 40 10

29 Question # 4 3x + 4= 7 1

30 Question # 5 (7 – x)2 = 9 4

31 Question # 6 8x + 3 = 27 3

32 Question # 7 1x – = 9 8

33 Question # 8 (x + 6) 4 = 32 2

34 Question # 9 (4x)2 = 144 3

35 Question # 10 (9x) + 4 = 4

36 The End


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