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Algebra (Solving Equations)
Lesson # 41 Algebra (Solving Equations)
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By Amanda Brown Of 803
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Solving Algebra Equations
Suppose you have an equation like 3x + 1 = 7 What would be the value of “x” to make this a “TRUE” statement?
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To find out the value of “x”
take the answer “7” and start working backwards.
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Whatever you do to the left side, must also be done to the right side.
3x + 1 = 7 Get rid of the + 1 first, by subtracting it from the left side of the equation. Whatever you do to the left side, must also be done to the right side.
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Therefore 3 times “x” must = 6.
So… subtract 1 from the 7 To leave you 6. Therefore 3 times “x” must = 6.
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That means… “X” must Equal 2
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Is a true mathematical statement…
See “ 3x + 1 = 7” Is a true mathematical statement… When X = 2
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What is the value of “X” in this equation:
Another example… What is the value of “X” in this equation: (4x)2 = 64
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4 times “x” has to be squared.
The answer to that must equal 64. Soooooo… Find the square root of 64… 8, right.
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So, then … 4 times what give you 8? 2
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So then … (4 x “2”)2 = 64
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And now… 10 Practice Questions
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For the next 10 questions…
Find the value of “X”.
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Question # 1 X + 31 = 36
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Question # 2 X + -3 = +7
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Question # 3 (6 - 2) x = 40
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Question # 4 3x + 4 = 7
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Question # 5 ( 7 – x ) 2 = 9
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Question # 6 8x + 3 = 27
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Question # 7 x – = 9
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Question # 8 (x + 6) 4 = 32
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Question # 9 (4x)2 = 144
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Question # 10 (9x) + 4 = 4
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And Now.. The Answers Prepare Yourself !
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Question # 1 X + 31 = 36 5
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Question # 2 X + -3 = +7 +10
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Question # 3 (6 - 2) x = 40 10
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Question # 4 3x + 4= 7 1
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Question # 5 (7 – x)2 = 9 4
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Question # 6 8x + 3 = 27 3
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Question # 7 1x – = 9 8
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Question # 8 (x + 6) 4 = 32 2
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Question # 9 (4x)2 = 144 3
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Question # 10 (9x) + 4 = 4
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The End
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